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N76
3 months ago
9

Triangle E F G is shown. Which statements regarding Triangle E F G are true? Select three options. E F + F G greater-than E G E

G + F G greater-than E F E G minus F G less-than E F E F minus F G greater-than E G E G + E F less-than F G
Mathematics
2 answers:
Zina [12.3K]3 months ago
8 0

Answer:

1) E F + F G is greater than E G

2) E G + F G is greater than E F

3) E G minus F G is less than E F

Step-by-step explanation:

I answered this correctly on Edg

zzz [12.3K]3 months ago
4 0

Answer:

The correct statements are options 1 (E F + F G > E G), 2 (E G + F G > E F), and 5 (E G + E F < F G).

Step-by-step explanation:

We have triangle EFG.

For any triangle with sides a, b, and c, these inequalities hold:

a+b>c\\ \\a+c>b\\ \\b+c>a

Specifically for triangle EFG:

  • EF+FG>EG;
  • EG+GF>EF;
  • FE+EG>FG.

Thus, the true statements are options 1, 2, and 5.

Statements 3 and 4 are incorrect.

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A semicircular flower bed has a diameter of 3 metres.
babunello [11817]

Answer:

3.5 m^2

Step-by-step explanation:

For a shape that is half a circle, use the formula: A = \frac{1}{2} π r^2

Calculate the radius, which is half of the diameter: r = d/2 = 3/2 = 1.5

Insert r = 1.5 into the formula.

A = \frac{1}{2} π 1.5^2

A = \frac{1}{2} (3.14) 1.5^2

Calculate the result with your calculator and round it off.

The final answer is 3.5

3 0
3 months ago
Read 2 more answers
Suppose log subscript a x equals 3, log subscript a y equals 7, and log subscript a z equals short dash 2. Find the value of the
AnnZ [12381]

Answer:

24

Step-by-step explanation:

Based on the logarithmic expressions given log_ax = 3, log_ay = 7, log_az = -2, we need to identify the value of log_a(\frac{x^3y}{z^4} )

from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}By substituting x = a³, y = a⁷, and z = a⁻² into the logarithmic function log_a(\frac{x^3y}{z^4} ), we will derive;

= log_a(\frac{x^3y}{z^4} )\\\\= log_a(\dfrac{(a^3)^3*a^7}{(a^{-2})^4} )\\\\= log_a(\dfrac{a^9*a^7}{a^{-8}} )\\\\= log_a\dfrac{a^{16}}{a^{-8}} \\\\= log_aa^{16+8}\\\\= log_aa^{24}\\\\= 24log_aa\\\\= 24* 1\\\\= 24

Therefore, the result of the logarithmic expression is 24

6 0
2 months ago
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