The standard kilogram (fig. 1.1a) is a platinum–iridium cylinder 39.0 mm in height and 39.0 mm in diameter. what is the density

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skad

2 months ago

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The standard kilogram (fig. 1.1a) is a platinum–iridium cylinder 39.0 mm in height and 39.0 mm in diameter. what is the density

of the material?

Mathematics

1 answer:

AnnZ [12.3K] · Answer 1 · 2026-03-24T02:45:46+03:00

The volume of a cylinder can be determined using the formula pi*h*d^2/4, which leads us to V = pi*(39 mm)(39 mm)^2 / 4 = 46,589 mm^3. Dividing the mass of 1 kg by the volume of 46,589 mm^3 results in a density of 2.1464 x 10^-5 kg/mm^3. Typically, density is expressed in kg/m^3, so we convert this by multiplying by 1x10^9, yielding a density of 21,464 kg/m^3.

The standard kilogram (fig. 1.1a) is a platinum–iridium cylinder 39.0 mm in height and 39.0 mm in diameter. what is the density

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