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fomenos
4 days ago
11

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.
1.) Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.

2.)Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.

3.)Write the equation in function notation. Explain what the graph of the function represents. Be sure to use complete sentences.

4.)Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology.

5.)Suppose Sal's total profit on lunch specials for the next month is $1,593. The profit amounts are the same: $2 for each sandwich and $3 for each wrap. In a paragraph of at least three complete sentences, explain how the graphs of the functions for the two months are similar and how they are different

6.)Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations

Mathematics
1 answer:
Inessa [9K]4 days ago
7 0
Let
x--------> <span>the total number of sandwich lunch specials sold
y-------> </span><span>the total number of wrap lunch specials sold

it's given that
2x+3y=1470

Part 1) </span><span>Convert the equation into slope-intercept form. Determine the slope and y-intercept of the equation. Remember to document your calculations.

we know that
</span>the standard form for slope-intercept is
y=mx+b
thus
2x+3y=1470------> isolate y
3y=1470-2x-----> divide both sides by 3
y=(-2/3)x+1470/3
y=(-2/3)x+490

the slope m=-2/3
the y-intercept is 490


Part 2) <span>Explain how to graph this line using the slope-intercept technique. Be sure to write in full sentences.

</span><span>the slope is -2/3 and the y-intercept is 490

Mark the point (0,490)------> the y-intercept.
From the slope, move 3 squares to the right and 2 squares down, then mark that point, which is (0+3,490-2)--------> (3,488)
Connect the two points with a straight line

Part 3) </span>Express the equation in function notation. Describe what the function's graph signifies. Ensure you use full sentences.

In function notation, the equation is:
f(x)=(-2/3)x+490
The graph of this function illustrates how the function's value changes with respect to the value of x. Within the context of the question, this graph specifically denotes how many wraps could have been sold for every number of sandwiches sold, maintaining an identical profit of $1470.<span>

Part 4) </span>Create the graph of the function. Ensure to label the intercepts on the graph. You may either draw the equation manually on paper and scan it or utilize graphing technology

via a graphing tool
see the attached figure

Part 5) Assume Sal's overall profit from lunch specials for the following month is $1,593. The profit amounts remain constant: $2 for each sandwich and $3 for every wrap. In a paragraph with at least three complete sentences, clarify how the graphs for the two months' functions are alike and how they differ

we have that
2x+3y=1593
3y=1593-2x--------> y=(-2/3)x+531
slope=(-2/3)
y intercept=531
therefore
similarities: same slope
differences: y intercepts are different.
<span>This indicates that the lines are parallel because they share the same slope.
</span>
6) Below is a graph depicting total profits for a third month. Formulate the equation of the line that corresponds to this graph. Show your methodology or describe how you derived the equations

Choose two points on the line and denote their coordinates

Let
A( 0,300) B (450,0)
a) calculate the slope
m=(y2-y1)/(x2-x1)----> m=(0-300)/(450-0)----> m=-2/3
b) Utilizing the slope m=(-2/3) and the point A (0,300)
y-y1=m*(x-x1)-----> y-300=(-2/3)*(x-0)----> y=(-2/3)x+300

the final answer for Part 6) is
y=(-2/3)x+300
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