Crane Company reports the following for the month of June.

To determine the time interval δt, we must subtract the starting time from the ending time. In this scenario, the first value in the coordinates signifies time:

δt=50 - 0
δt= 50s

The time interval is 50s.

Bart needs to;

Calculate 6(400), 6(10), and 6(2) ⇒ 2nd

Calculate each addend multiplied by 6 ⇒ 4th

Determine the total of (2400 + 60 + 12) ⇒ 5th

Step-by-step breakdown:

We'll review the distributive property

• a(b + c) = ab + ac
• a(b + c + d) = ab + ac + ad

Bart applied place value along with the distributive property to express the

calculation 6(412)

His calculation can be represented as 6(412) = 6(400 + 10 + 2)

We must find out what Bart needs to do to compute the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply every component inside the brackets by 6 on the right side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should multiply each addend by 6, then calculate the total of

  (2400 + 60 + 12)

Bart needs to;

Calculate 6(400), 6(10), and 6(2)

Multiply each addend by 6

Compute the total of (2400 + 60 + 12)

Learn more:

You can find additional information regarding place value at

Response:

2(3-n)+5.

Clarification:

Twice a number plus five equals three times the difference between that number and two. "More" indicates addition, hence twice the number is represented as multiplying N (or whatever variable) with the determination that it equals three times the reduction of that number and two.

We cannot infer that the proportion of wives married less than two years intending to have children is significantly greater than that of those married for five years.

 x = 27 + 3 √ 129/ 4, 27 − 3 √ 129/ 4

Please note: the entire equation mentioned is divided by 4, not only the last term. 

 x approximates to 15.26836251, − 1.76836251

That concludes my response. I hope this is helpful. You will still need to work on finding y and z, which can be quite challenging:)