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LUCKY_DIMON
1 month ago
6

Suppose that a 10-Mbps wireless station is transmitting 50-byte frames one immediately after the other.

Computers and Technology
2 answers:
zubka84 [1K]1 month ago
7 0
1 byte = 8 bits

10 Mbps corresponds to 10/8 M bytes per second

Each frame size = 50 bytes

Frames per second = 10 M / (8 × 50) = 10 M / 400 = 25,000 frames every second

========================

With a per-frame error probability of 0.004, (0.004 × 25,000) = 100 frames per second are corrupted.

An hour contains 3,600 seconds.

Therefore 100 corrupted frames per second equals (100 × 3,600) = 360,000 corrupted frames each hour.
Harlamova29_29 [1K]1 month ago
6 0
One megabyte contains 1'000'000 Bytes, so 10 Megabytes contain 10'000'000 Bytes. If frames were 1 Byte each, that would yield 10'000'000 frames. However, since frames are 50 Bytes, divide 10'000'000 by 50.

Thus the answer for part (i) is: 200'000 Framesper second

With 200'000 frames each second, over one hour there are 200'000 × 60 = 12'000'000 frames/hour

Given a damaged-frame probability of 0.004, multiplying 0.004 by 12'000'000 yields (ii) 48'000 Damaged Frames/hour
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2 months ago
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Harlamova29_29 [1022]

Response:

C++ code provided below with suitable annotations

Clarification:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

cout<<" ";

}

cout<<"\n";

}

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

int main()

{

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<<endl;

cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;

cin>>num>>ch;

if(ch=='x' || ch=='X')

printCross(num);

else if(ch=='f' || ch=='F')

printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

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