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LUCKY_DIMON
10 days ago
6

Suppose that a 10-Mbps wireless station is transmitting 50-byte frames one immediately after the other.

Computers and Technology
2 answers:
zubka84 [945]10 days ago
7 0
1 byte = 8 bits

10 Mbps corresponds to 10/8 M bytes per second

Each frame size = 50 bytes

Frames per second = 10 M / (8 × 50) = 10 M / 400 = 25,000 frames every second

========================

With a per-frame error probability of 0.004, (0.004 × 25,000) = 100 frames per second are corrupted.

An hour contains 3,600 seconds.

Therefore 100 corrupted frames per second equals (100 × 3,600) = 360,000 corrupted frames each hour.
Harlamova29_29 [932]10 days ago
6 0
One megabyte contains 1'000'000 Bytes, so 10 Megabytes contain 10'000'000 Bytes. If frames were 1 Byte each, that would yield 10'000'000 frames. However, since frames are 50 Bytes, divide 10'000'000 by 50.

Thus the answer for part (i) is: 200'000 Framesper second

With 200'000 frames each second, over one hour there are 200'000 × 60 = 12'000'000 frames/hour

Given a damaged-frame probability of 0.004, multiplying 0.004 by 12'000'000 yields (ii) 48'000 Damaged Frames/hour
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Answer:

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