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Sloan
3 months ago
15

Bill's new porch is rectangular, with an area of 50 square feet. If the length of the porch is two times the width, what is the

perimeter of the porch?
Mathematics
1 answer:
lawyer [12.5K]3 months ago
4 0
1. The area of a rectangle is given by:

 A = L × W

 Where L is length (L = 2W) and W is width.

2. Substituting L = 2W into the area formula:

 A = 2W × W = 2W²

3. Solving for W:

 W² = A / 2
 W = √(A / 2)

4. Using A = 50 ft²:

 W = √(50 / 2) = √25 = 5 ft

5. Finding L:

 L = 2 × 5 ft = 10 ft

6. The perimeter P is:

 P = 2L + 2W

7. Therefore:

 P = 2 × 10 ft + 2 × 5 ft = 20 ft + 10 ft = 30 ft

The porch's perimeter is 30 ft
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Each of the six payments amounts to $41.50

Step-by-step breakdown:

Given,

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Initial payment = $100

Remaining balance = Total cost of bike - Initial payment

Remaining balance = 349 - 100

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Monthly payment = \frac{Amount\ left\ to\ pay}{No.\ of\ months}

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Each of the six payments amounts to $41.50

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2 months ago
Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =
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Answer:

The distance from the point (0,1,1) to the specified line is zero.

Step-by-step explanation:

Considering the parametric equations of the line,

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\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0

The distance between the point (0,1,1) and (1) amounts to zero. Therefore, the point (0,1,1) is located on the line (1).

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Hi! I'm confused with this question, It's about tessellations. Can someone give a complete example of a possible answer? It woul
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Yes, this reflects the correct answer as [[TAG_10]]
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