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professor190
15 hours ago
8

There are two cables coming off the top of a building from the same point. Each cable is secured to the ground. The longest cabl

e is 200 ft. It is attached at point M and creates a 32° angle of elevation with the ground. The other cable is attached at point N. If the angle formed between the two cables at the top of the building is 25°, what is the distance between points M and N?
Measure of Ð N =
°
Mathematics
2 answers:
Zina [9.1K]14 hours ago
6 0

Designate the attachment point atop the building as point T (Angle T = 25°). The angle N will be calculated as 180° -32° -25° = 123°. According to the Law of Sines, the relationship is established as...

... TM/sin(N) = MN/sin(T)

... Consequently, MN = TM·sin(T)/sin(N) = (200 ft)·sin(25°)/sin(123°)

... MN is approximately 100.8 ft

lawyer [9.2K]15 hours ago
3 0

Answer:

N= 123

x= 100.8

Step-by-step explanation:

I just worked through it

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