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shutvik
12 days ago
11

A professor believes that students at her large university who exercise daily perform better in statistics classes. Since all st

udents at the university are required to take Introduction to Statistics, she randomly selects 17 students who exercise daily and 22 students who exercise at most once per week. She obtains their scores in the final exam in Introduction to Statistics and finds that the students who did not exercise daily primarily produced scores in the 90s, with some scores in the 80s and a very few scores in the 70s and 60s. The students who did exercise daily also had a large number of scores in the 90s and an almost equal number in the 60s, with very few scores in between. Would it be valid for the professor to use the independent-measures t test to test whether students at her large university who exercise daily perform better in statistics classes?
Mathematics
1 answer:
Leona [12K]12 days ago
7 0

Response: Yes, it is

Detailed explanation:

Since the average scores of both sets of students vary, evaluating the mean score in relation to their class will clarify which class supports or contradicts the professor's research

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Aaron draws a segment in his notebook. What is the minimum number of points through which the segment is drawn?
PIT_PIT [11881]

Answer:

The result is 2

Step-by-step explanation:

A segment requires at least 2 points for its construction.

In geometry, a line segment refers to a section of a line defined by two unique endpoints, encompassing all points located along the line segment between these endpoints.

5 0
1 month ago
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The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [11812]
\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
29 days ago
Read 2 more answers
Twelve of the 20 students in Mr. Skinner’s class brought lunch from home. Fourteen of the 21 students in Ms. Cho’s class brought
Svet_ta [12268]

Solution:

In Mr. Skinner's class, the count of students bringing lunch from home is 12 out of 20.

Fraction of students who brought lunch from home in Mr. Skinner's class=\frac{12}{20}=\frac{3}{5}

For Ms. Cho's class, the number who brought lunch from home is 14 out of 21.

Fraction of students who brought lunch from home in Ms. Cho's class=\frac{14}{21}=\frac{2}{3}

Siloni is utilizing two spinners with 15 equal sections to randomly select students from the classes and predict whether they brought lunch or will purchase it from the cafeteria.

Number of Equal sections in each Spinner=15

To visualize the students from Mr. Skinner's class who brought lunch using a Spinner with 15 equal sections =\frac{9}{15}

For Ms. Cho's class, using a Spinner with 15 equal sections =\frac{10}{15}

Mr. Skinner's Class +1 = Ms. Cho's Class

This means that the spinner for Ms. Cho's class will include one additional section representing students who brought lunch.

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9 0
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A=9y+3yx solve for y
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The solution for y is y = \frac{a}{3(3 + x)}
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A pharmacy uses 4×10−3 liter of an active ingredient in one dose of a medication. The active ingredient comes in a 2-liter bottl
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Each bottle contains 2 liters of the active solution. To find out how many doses can be made, divide 2 L by 4x10^-3.
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