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NNADVOKAT
22 days ago
12

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh

t (y).
Y=-0.02x^2+0.8x+3


What will the height of the ball be at a distance of 10 feet?


A. 6
B. 7
C. 8
D. 9
Mathematics
1 answer:
babunello [11.8K]22 days ago
6 0
D). 9 ft is indeed the correct answer. The height of the ball at a horizontal distance of 10 feet is 9 ft.
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An upscale resort has built its circular swimming pool around a central area that contains a restaurant. The central area is a r
zzz [12365]
The diagram below illustrates the issue at hand.

Question 1:
The maximum area of the pool equals half the area of the circle.

To calculate the area of the circle: Area = πr², with r being half of the diameter.
Thus, Area of circle = π(60)² = 11309.73355 square feet.

Therefore, the area representing half the circle amounts to 11309.73355/2 = 5654.866... ≈ 5654.87 square feet (rounded to 2 decimal places).

Question b:

To find the pool's area, we take the circle's area and subtract the triangle's area.

The area of the circle is 11309.73 square feet.

For the triangle's area calculation: 1/2 × (60×103.92) = 3117.6 square feet.

The area of the pool thus operates as 11309.73 - 3117.6 = 7922.13 square feet.

Calculating the pool's volume: 7922.13 × 4 = 31688.52 cubic feet.

Note: Information related to the fish tank is unavailable, so the above calculation focuses solely on the entire pool's volume.

6 0
1 month ago
g A modal class in a histogram is the class that includes a. the largest number of observations. b. the smallest observation in
Leona [12618]

Answer:

a. the class with the highest number of observations.

Step-by-step explanation:

The mode refers to the value within a dataset that appears most frequently. This indicates that it occurs with greater frequency than other values.

In a histogram, the modal class denotes the category that has the most observations, demonstrating that the variables in that category have a higher occurrence than those in others. Consequently, the answer sought is option a.

4 0
10 days ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
Inessa [12570]

Answer: D) \$50\pm\$11.08

Step-by-step explanation:

Based on the provided information, we have

Sample size: n= 15

sample mean: \overline{x}=\$50.50

Sample standard deviation: s= $20

Since the population standard deviation is not known, we utilize a t-test.

For a significance level of 95% confidence: \alpha=1-0.95=0.05

Critical t-value : t_{n-1, \alpha/2}=t_{014,0.025}=2.145  [Using the Student's t-value table]

The required 95% confidence interval yields:-

\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08

Thus, the sought-after 95% confidence interval for the mean amount spent by credit card customers during their initial visit to the new store in the mall, assuming normal distribution of the spending amounts, is:

\$50\pm\$11.08

5 0
26 days ago
A machine makes a box in 1 3/10 secs. How many boxes can the machine make in a hour? Please show work
AnnZ [12381]
The total is 4 boxes, as you don't count the.6 since it's not a complete box.
5 0
23 days ago
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per mont
AnnZ [12381]

Response:

The monthly income of Kim's business is $10,000.

Every month, Kim spends $3,000 on non-employee costs.

To achieve a monthly profit of $2,000, the highest possible expenditure for employees is calculated as follows:

10000 - 3000 - 2000 = 5000

With the cost of each employee being $1,000 a month, Kim can hire a maximum of 5000/1000 = 5 employees.

Hope this is useful

:)

8 0
1 month ago
Read 2 more answers
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