In Mendel's work with peas, an F1 hybrid (smooth yellow) was crossed to the recessive (wrinkled green) parent type. In terms of

Answer:

The offspring include smooth yellow (SsYy), smooth green (Ssyy), wrinkled yellow (ssYy), and wrinkled green (ssyy).

Consequently, the percentages of phenotypes observed in these offspring from the cross stand at 25% each.

Explanation:

Provided;

Here the parental genotypes consist of an F1 hybrid smooth yellow and the recessive wrinkled green;

The F1 hybrid smooth yellow can be designated as SsYy

S = smooth; S is the dominant allele over s,Y = yellow; Y is the dominant allele over y.

The potential offspring will comprise

The gametes of ssyy equal; sy

Therefore, the resulting offspring will exhibit genotypes: SsYy, Ssyy, ssYy, and ssyy.

And phenotypes are smooth yellow (SsYy), smooth green (Ssyy), wrinkled yellow (ssYy), and wrinkled green (ssyy).

As such, the prevalence of the phenotypes among the offspring of this cross is 25% each.