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Ne4ueva
1 month ago
7

1. You are given the task to quantify the bacteria in your soil sample. You do a 10-fold serial dilution of your soil sample in

sterile water and plate 1/10 of each subsequent (serial) dilution in LB agar plates with cycloheximide – an antifungal and eukaryotic cell inhibitor. If your 10–6 (ten to the minus sixth) dilution plate contains 97 bacterial colonies after two days of incubation, how many bacteria can you estimate were present in your initial soil sample (1 g of soil)? Show your calculation and briefly describe each step.
Biology
1 answer:
lana [2.4K]1 month ago
8 0
Conducting a serial dilution along with a plating experiment allows for the quantification of bacteria or microbes present in a specified volume of a soil sample. In this standard procedure, a designated volume taken from the lesser dilution is placed on a median plate, which is then allowed to incubate for the appropriate duration. The resulting colonies are counted to ascertain the overall Colony Forming Units (CFU) based on the volume of the sample that was plated and the amount of soil sample that was utilized. The calculation follows this formula: CFU/ml = Number of colonies counted × dilution factor / volume plated. In this scenario, we have: Number of colonies counted = 97, dilution factor = 10^(-6), and volume plated = 1/10 = 0.1. Therefore, the calculation proceeds as: CFU/ml = 97 * 10^(-6) / 0.1 = 97 * 10^(-7) CFU/ml. This figure represents the concentration of bacterial colonies per unit volume of the plated sample. Given that the original soil sample weighs 1g or 1000 mg, the total number of bacteria can be estimated with this formula: Amount of bacteria in original sample = 97 * 10^(-7) CFU/ml × 1/1000 mg = 9.7 * 10^(-3) CFU/mg.
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