U.s. internet advertising revenue grew at the rate of r(t) = 0.82t + 1.14 (0 ≤ t ≤ 4) billion dollars/year between 2002 (t = 0)

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U.s. internet advertising revenue grew at the rate of r(t) = 0.82t + 1.14 (0 ≤ t ≤ 4) billion dollars/year between 2002 (t = 0)

and 2006 (t = 4). the advertising revenue in 2002 was $5.9 billion.† (a) find an expression f(t) giving the advertising revenue in year t.

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Katen [3.5K] · Answer 1 · 2026-03-29T07:49:57+03:00

Where C represents a constant, utilizing the provided initial condition yields: And by resolving for C, we determined: The aspirational function for advertising revenue can then be expressed as: Here, f represents the amount in billions, and denotes the years from 2002 to 2006. In this context, the following function illustrates the revenue growth rate. To ascertain the Advertising revenue, we must integrate the function r(t), applying the initial condition t=0, with f(2)= 5.9 billion. Upon integration, we arrive at: Utilizing the initial condition gives us: After resolving for C, we find: Therefore, the desired function for advertisng revenue takes the form displayed, accounting for f in billions of dollars during the years 2002 to 2006.

U.s. internet advertising revenue grew at the rate of r(t) = 0.82t + 1.14 (0 ≤ t ≤ 4) billion dollars/year between 2002 (t = 0)

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