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Nana76
11 days ago
13

A warren of rabbits has a population of 25. The population is increasing at a rate of 20% per year. How can you write an exponen

tial growth function to find the monthly growth rate?
Mathematics
1 answer:
tester [11.9K]11 days ago
6 0

Answer:

(Refer to explanation)

Step-by-step explanation:

The differential equation associated with exponential growth is:

\frac{dn}{dt} = k\cdot n

The formula is rearranged and later integrated:

\frac{dn}{n} = k \cdot dt

\int\limits_{n_{o}}^{n} {\frac{dn}{n} } = k\cdot \int\limits_{0}^{t}\, dt

\ln \frac{n}{n_{o}} = k\cdot t

\frac{n}{n_{o}} = e^{ k\cdot t}

n = n_{o}\cdot e^{k\cdot t}

An exponential growth function can help identify the monthly growth function as follows:

\ln 1.2 = k\cdot 12

k = 0.015

The coefficients found in the expression are, respectively:

n_{o} = 25

k = 0.015

The monthly exponential growth function is presented as:

n(t) = 25\cdot e^{0.015\cdot t}, where t is expressed in months.

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