Amy is 1 year older than Ben. The sum of their ages is greater than 33 and less than 45 Find all possible ages of Ben

Complete question:

Benjamin treats himself to breakfast at his go-to restaurant. He orders chocolate milk priced at \$3.25$3.25dollar sign, 3, point, 25. Next, he aims to purchase as many pancake stacks as possible while keeping his total at or below \$30$30dollar sign, 30 prior to tax. Pancakes are sold in stacks of 4 at \$5.50$5.50dollar sign, 5, point, 50. Let SSS denote the number of pancake stacks purchased by Benjamin. 1) What inequality represents this situation?

Answer:

Refer to the explanation below.

Step-by-step explanation:

Information provided:

Chocolate milk costs = $3.25

Price of pancake stack = $5.50 (for 4 pancakes)

Pancake stacks bought = S

Maximum spending ≤ $30

Chocolate milk cost + (Cost per pancake stack × number of stacks) ≤ $30

3.25 + 5.50S ≤ 30

5.50S ≤ 30 - 3.25

5.50S ≤ 26.75

S ≤ 26.75 / 5.50

S ≤ 4.86

Therefore, the maximum number of pancake stacks he can buy without going over budget is 4.

Thus, total pancakes = stacks × pancakes per stack

= 4 × 4

= 16

Thank you for bringing your question here. I hope you find the answer useful. Don't hesitate to ask additional questions. Yes, as the level of tar rises, the concentration of carbon monoxide also increases.

Answer:

The result is 2

Step-by-step explanation:

A segment requires at least 2 points for its construction.

In geometry, a line segment refers to a section of a line defined by two unique endpoints, encompassing all points located along the line segment between these endpoints.

Answer: (97.98, 112.020)

Step-by-step explanation: We will create a 95% confidence interval for the average weight of melons.

Given the information, we determine that the critical value for the interval needs to be retrieved from a t distribution table due to the sample size being below 30 (specifically, 20), and we are provided with the sample standard deviation (s = 15 lb).

The parameters provided are:

Sample mean = x = 105 lb

Sample standard deviation = s = 15 lb

Sample size = n = 20

To establish the 95% confidence interval, we indicate that the level of significance is 5%.

The formula for the confidence interval is:

u = x + tα/2 × s/√n... for the upper limit

u = x - tα/2 × s/√n... for the lower limit.

tα/2 represents the critical value for the test (which will be determined using the t distribution table).

To derive tα/2, we look for the value based on the degrees of freedom (sample size - 1) against the significance level for a two-tailed test (α/2 = 0.025%) in a t distribution table.

For the upper limit, we calculate:

u = 105 + 2.093×15/√20

u = 105 + 2.093× (3.3541)

u = 105 + 7.020

u = 112.020.

<pfor the="" lower="" limit="" we="" find:="">

u = 105 - 2.093×15/√20

u = 105 - 2.093× (3.3541)

u = 105 - 7.020

u = 97.98

Confidence interval (97.98, 112.020)

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