For each property listed, identify the type of element it describes. Very good electrical conductivity: Amphoteric, able to form
2 answers:
You might be interested in
Answer:
La magnitud del EMF es 0.00055 volts
Explanation:
El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:
Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:
Necesitamos expresar el flujo magnético dada la geometría del problema;
donde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:
Answer:
B= ≅8.06
Explanation:
Applying the Pythagorean theorem:
=
+
Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.
=
+
81= 16+
81-16=
B= ≅8.06
Answer:
The density comes out to be Mg/µL
Explanation:
Given data:
The density of nuclear matter is approximately kg/m³
1 ml corresponds to 1 cm³
To determine:
The density of nuclear matter in Mg/µL
Solution:
We recognize that:
1 Mg equals 1000 kg
Thus, 1 m³ is equal to cm³
Moreover, 1 cm³ is equivalent to 1 mL
Thus, we can conclude that 1 mL is equal to 10³ µL
With this, we convert the density as follows:
Density = kg/m³
Density = kg/m³ ×
Mg/µL
Density = Mg/µL