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Arada
3 months ago
15

When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

ttom of a long, straight road with constant upward slope. If Rob takes 5.0 minutes to reach thetop, how much earlier should Jim start in order to reach the top at the same time as Rob
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
7 0

Answer:

46.4 seconds

Explanation:

5 minutes converts to 60 times 5, giving us 300 seconds.

Take g = 9.8 m/s². Let \theta represent the slope, s the distance, a the acceleration of Rob, with Jim achieving 3a/4 for his acceleration. Their motions are influenced by the parallel component of gravitational acceleration gsin\theta.

For Rob, the motion can be modeled as s = a_Rt_R²/2 = a300²/2 = 45000a.

Jim's motion equation is as shown in s = a_Jt_J^2/2 = (3a/4)t_J^2/2 = 3at_J^2/8.

Both cover equal distances, indicated by 45000a = 3at_J^2/8.

t_J^2 = 45000*8/3 = 120000

t_J = \sqrt{120000} = 346.4 s

Thus, Jim must start 46.4 seconds before Rob to arrive simultaneously at the top.

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If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
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Answer:

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Consequently, the temperature difference across the material will be \Delta T = 375 K

Explanation:

In this case, we apply the Fourier Law of heat conduction expressed by the following equation:

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Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 denotes the cross-sectional area

Q= 3KW signifies the heat transfer rate

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represents the thickness of the material\Delta x=2.5 cm =0.025 m

To isolate \Delta T from equation (1), we obtain:

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Initially, we convert 3KW to W, resulting in:

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With all variables accounted for, we can substitute and calculate:

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