Part A
To identify the values of x that make 2x−1 positive
⇒ 2x - 1 > 0
⇒ 2x > 1
⇒ x > 
As a result, for any x greater than

, the expression 2x-1 is positive
Part B
To find values of y making 21−37 negative
⇒ 21-3y < 0
⇒ 21 < 3y
⇒ 7 < y
Thus, for all y values exceeding 7, the expression 21-3y is negative
Part C
To identify values of c that digit 5−3c greater than 80
⇒ 5-3c > 80
⇒ -3c > 75
⇒ -c > 25
⇒ c < -25
Therefore, for values of c less than -25, the expression 5-3c surpasses 80
Response:
x ≥ 4
Step-by-step breakdown:
Given
- 4(8 - 3x) ≥ 6x - 8 ← distribute the term in parentheses on the left side
- 32 + 12x ≥ 6x - 8 (subtract 6x from both sides)
- 32 + 6x ≥ - 8 (add 32 to both sides)
6x ≥ 24 (divide both sides by 6)
Thus, x ≥ 4
The students likely won't care much about the spending because they aren't using their own money.