There were 2.605 people at the basketball game. A reporter rounded this number to the nearest hundred from a newspaper article.

one must evaluate 12 minus 5B9 as the base and remember to include the integer

Answer:

a) 11,880

b) 495

c) 0.00202

Step-by-step explanation:

Given:

Here is the full question:

"A corporation needs to select a president, chief executive officer (CEO), chief operating officer (COO), and chief financial officer (CFO). It also needs to form a planning committee comprising four distinct members. There are 12

qualified candidates, and the officers can also serve on the committee.

Find:

a. Determine the number of ways to appoint the officers.

Solution:

- Total qualified candidates = 12

 - Number of officers to appoint = 4 (President, Chief Executive Officer, Chief Operating Officer, Chief Financial Officer)

- Since the order matters, we use permutations:

- The number of different arrangements to appoint officers = 12P4 = 11,880

b. Determine the number of ways to select the committee members.

   Total qualified candidates = 12

  The number of planning committee members = 4  

  Here, order doesn't matter, so we use combinations:

  The number of different ways to form a committee = 12C4 = 495

   

c. What is the likelihood of randomly choosing the committee members being the four youngest qualified candidates?

  P ( 4 youngest officers ) =  Chances of selecting 4 youngest / Total number of committees

                                           = 1 / 495

                                           = 0.00202

Answer:

or approximately 57.88

Step-by-step explanation:

To compute the base length, we employ the triangular area formula.

Insert the known values for the area and height to find .

or close to 57.88 when rounded to two decimal places.

According to the stated conditions, the quantity of bacteria at any time t (in hours) can be determined using the following equation,
                                         at = (a1)(2^t/2)

where a1 denotes the initial bacteria count and at represents the count at time t. By using the provided numbers,
                                      a6 = (103)(2^6/2) = 824 

Consequently, there are 824 bacteria present after 6 hours. 

Response: f of 3 equals 2, while f of 2 equals negative.

Detailed breakdown: