Answer:
E 240
Step-by-step explanation:
Mean of the geometric distribution = (1- p) / p
16 = (1 - p) / p
16p = 1 - p; 17p = 1; thus, p = 1/17 = 0.058
Standard Deviation = (1 - p) / p^2
= (1 - 0.058) / (0.058)^2
0.942 / 0.003364
= 280, which is closest to 240
When the balloon touches the ground, a(t) will equal zero.
To calculate the time it takes to reach the ground, the equation can be set up as follows:
210 - 15t = 0
Solving this yields t = 210/15, equating to 14 minutes.
Answer:
Step-by-step explanation:
I'm fairly certain that addition is needed here.
When we combine two fractions like 3/4 + 3/4, we ensure that the denominators (the bottom parts) are identical before simply adding the numerators (the top parts).
In this case, the denominators match, so we straightforwardly combine 3+3 to get 6/4. The denominator remains the same.
answer:
3/4 + 3/4 = 6/4
Hope this helps!
Utilize the details to create inequalities that reflect each limitation or requirement.
2) Label the
variables.
c: count of color copies
b: count of black-and-white copies
3)
Define each constraint:
i) <span>Printing a color copy requires 3 minutes while a black-and-white copy takes 1 minute.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He must print
a minimum of 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) Moreover, he must finish the prints within
12 minutes at most ⇒</span>
3c + b ≤ 12<span />
4) Additional limits include
c ≥ 0, and
b ≥ 0 (meaning
only non-negative counts are valid for each type of copy)
5) Here’s how to
illustrate that:
i) For 3c + b ≤ 12: draw the line representing 3c + b = 12 and shade the area above and to the right of this line.
ii) For c + b ≥ 6: draw the line c + b = 6 and shade the area below and to the left of this line.
iii) Given that c ≥ 0 and b ≥ 0, the relevant region is located in the
first quadrant.
iv) The concluding area is the
overlap of the previously mentioned shaded regions.v) The graph can be viewed in the attached figure.
(a) The likelihood that all 5 eggs chosen are unspoiled is 0.0531. (b) The probability that 2 or fewer out of the 5 eggs are unspoiled is 0.3959. (c) The probability that more than 1 of the selected 5 eggs are unspoiled is 0.8747. Step-by-step explanation: The complete query is: A subpar carton of 18 eggs has 8 that are spoiled. An unsuspecting chef selects 5 eggs at random for his “Mega-Omelet Surprise.” Calculate the probability of receiving (a) exactly 5 unspoiled eggs, (b) 2 or fewer, and (c) more than 1 unspoiled egg. Define X = number of unspoiled eggs. In the faulty carton, 8 eggs are spoiled. The probability of selecting an unspoiled egg is independent of others. Provided that a chef randomly picks 5 eggs, the variable X follows a Binomial distribution with parameters n = 5 and p = 0.556. Success is defined as selecting an unspoiled egg. The probability mass function of X is as follows: (a) Calculate the probability of selecting all unspoiled eggs. Thus, this probability is found to be 0.0531. (b) For 2 or less unspoiled eggs, the probability is computed: P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2), resulting in a probability of 0.3959. (c) For more than 1 unspoiled egg: P (X > 1) = 1 - P (X ≤ 1), yields a final probability of 0.8747.