A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at th
e same height as the connection point between the rope and weight. The distance from the connection point to the ceiling is 40 ft. Suppose the worker stands directly next to the weight (i.e., a total rope length of 80 ft) and begins to walk away at a constant rate of 2 ft/s. How fast is the weight rising when the worker has walked: 10 feet? Answer = 30 feet? Answer =
1 answer:
Answer:0.246 ft/s
Step-by-step explanation: As the worker starts moving and stops 10 feet away from the side rope connected to the load, it creates a right triangle, as illustrated in the image.
V = s/t... equation 1
S = distance the worker travels while pulling the rope = 10 ft
V = worker's velocity = 2 ft/s
T = time it takes for the worker to cover 10 ft = the same time the load takes to rise = 5 seconds
Using Pythagorean theorem to find the distance from the pulley to the new position of the worker
Square root of (40^2 + 10^2) = 41.23 ft
Distance covered by load = D = 41.23 - 40
= 1.23 ft
Load speed = D/t...equation 2
Substituting D and t into equation 2 gives us
Load speed = 1.23/5 = 0.246 ft/s
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