"A random sample of 50 university admissions officers was asked about expectations in application interviews. Of these sample me
2 answers:
Answer:
Statistical data suggests that the sample proportion stands at exactly 0.50.
Step-by-step explanation:
This follows from a random sample of 50 university admissions officers surveyed regarding their expectations during application interviews.
Sample proportion =
(Right tailed test at 5% significance level)
p difference = 0.06
Assuming H0 is valid, p will exhibit a normal distribution with
standard error =
Test statistic = p difference/std error
=
=0.8485
p value = 0.19808
Given that the p value exceeds alpha, the null hypothesis is accepted
Statistical data suggests that the sample proportion stands at exactly 0.50.
Answer:
A study involving 50 university admissions officers surveyed about their expectations during interview applications.
Sample proportion =
(Right-tailed analysis at 5% significance level)
Assuming H0 is accurate, p follows a normal distribution with
standard error =
The test statistic is calculated as the difference in p divided by standard error=Consequently, we do not have statistical grounds to claim that the sample proportion is greater than 0.50
You might be interested in
Answer with explanation:
Let’s consider: An urn is composed of 2 red marbles and 3 blue marbles.
Total number of marbles = 2 + 3 = 5
a) The possible ways for the person to select one red marble and one blue marble include:
1) Drawing a red marble first, followed by a second blue marble.
2) Drawing a blue marble first and then picking a red marble second.
b) The total number of combinations for selecting one red and one blue marble is represented as:-
(i)
c) The count of ways to draw 2 marbles from 5 is defined as:-
(ii)
Now, the probability of the individual selecting a red and a blue marble can be calculated as:-
[Divide (i) by (ii)]
Consequently, the probability of selecting a red and a blue marble= 0.6