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Maksim231197
14 days ago
15

Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?

Mathematics
2 answers:
Inessa [12.5K]14 days ago
8 0
<span>f(x)=x^2+6x+3
     =(1/2.6)^2=3^2=9
f(x)=(x^2+6x+9)+3-9
     =(x+3)^2-6</span>
Leona [12.6K]14 days ago
7 0
Answer: B. f(x) = (x + 3)^2 − 6 Step-by-step explanation: I used the method of completing the square for this. I hope this was helpful!
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Question Number 12 You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the l
babunello [11817]

Answer:

Length\: of\: D=37\frac{3}{16} \:feet

Step-by-step explanation:

Here are the details provided:

  • The handicapped space measures 10\frac{1}{16} feet next to the curb.
  • The other three spaces each are 8\frac{3}{8} feet wide.
  • There are four lines separating the spaces, each line being \frac{1}{2} foot long.

The Median D will be calculated as follows:

  • Width of the handicapped spot
  • 3 times the width of the other spaces
  • 4 times the width of the lines

= 10\frac{1}{16} + (3 X 8\frac{3}{8})+(4 X\frac{1}{2})\\=\frac{161}{16} + \frac{3 X 67}{8}+\frac{4}{2}\\=\frac{161}{16} + \frac{201}{8}+\frac{4}{2}\\=\frac{161+402+32}{16}\\=\frac{595}{16}\\Length\: of\: D=37\frac{3}{16} \:feet

7 0
1 month ago
What is the monthly finance charge if the average daily balance is $15, the daily periodic rate is 0.06%, and the number of days
Leona [12618]

Given

The daily average balance is $15.

The daily periodic interest rate = 0.06%.

The cycle consists of 30 days.

Calculate the monthly finance charge.

To justify:

Let’s denote the monthly finance fee as x.

According to the details provided:

The average daily balance = $15.

The daily periodic rate = 0.06%,

First, we convert 0.06% to decimal:

=\frac{0.06}{100}

= 0.0006.

Daily finance charge =  0.0006 multiplied by 15.

                                   =  0.009.

The number of days in the cycle totals 30.

Now, calculating the monthly finance charge:

The equation becomes:

x = 15 × 0.0006 × 30.

x = 0.009× 30.

x  = $0.27.

Thus, the monthly finance charge amounts to $0.27.

Thus proved.









4 0
1 month ago
Use the binomial theorem to find the coefficient of xayb in the expansion of (5x2 + 2y3)6, where a) a = 6, b = 9. b) a = 2, b = 15.
zzz [12365]

Answer:

Step-by-step explanation:

                    1

                1      1

            1      2      1

         1     3      3      1

      1    4     6       4       1

   1   5    10     10       5     1

 1    6   15   20      15    6     1

1    6   15   20      15    6     1

We employ these for the expansion of (5x² + 2y³)⁶

1(5x²)⁶(2y³)⁰ + 6(5x²)⁵(2y³)¹ + 15(5x²)⁴(2y³)² + 20(5x²)³(2y³)³+  15(5x²)²(2y³)⁴+ 6(5x²)¹(2y³)⁵ + 1(5x²)⁰(2y³)⁶

78125ₓ¹²+187500ₓ¹⁰ y³ +37500ₓ⁸y⁶+20000ₓ⁶y⁹+6000x⁴y¹²+960x²y¹⁵+2y¹⁸

a.)a = 6, b = 9. the coefficient of xᵃyᵇ ( 20000ₓ⁶y⁹) = 20000

b) a = 2, b = 15. the coefficient of xᵃyᵇ ( 960x²y¹⁵) = 960

c) a = 3, b = 12. the coefficient of xᵃyᵇ is not present

d) a = 12, b = 0 the coefficient of xᵃyᵇ ( 78125ₓ¹²)  = 78125

e) a = 8, b = 9. the coefficient of xᵃyᵇ is not present

7 0
26 days ago
Harmony used discarded paper to make notepads for her friends. She would fold five letter size pieces of paper three times then
zzz [12365]
Initially, the first fold creates two smaller sheets of paper
. The second fold of these sheets results in 4 smaller pieces of paper
. A third fold of the resultant pieces leads to 8 smaller pieces of paper

. Therefore, when five letter-sized sheets are folded three times, they yield 8 x 5 = 40 notes

. Consequently, one notepad comprises 40 notes

. If an individual writes ten notes daily, a single notepad will last for 4 days
.
7 0
1 month ago
Read 2 more answers
According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo
tester [12383]

Answer:

B. The average amount of CO_2 emitted by the new fuel is indeed beneath 89 kg, yet they fail to determine it is less than 89 kg

Step-by-step explanation:

A Type II error refers to the lack of rejection of a false null hypothesis.

Considering the null and alternative hypotheses of a gasoline company that seeks to evaluate a new gasoline type intended to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu signifies the mean amount of CO_2 emitted from burning one gallon of this novel gasoline.

If the null hypothesis is not correct, then:

H_a: \mu < 8.9 kg

Not asserting the alternative hypothesis will represent a Type II error.

Hence:

The Type II error can be described as: (B) The mean amount of CO_2 emitted by the new fuel is actually less than 89 kg but they mistakenly conclude it is greater than 89 kg.

8 0
15 days ago
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