The tiles in the floor of a bathroom are 15/16 inch squares. The cement between the tiles

The largest common divisor (GCD) here is 24, indicating how many identical sets can be created. To find this using Euclid's algorithm, you start by dividing the larger number (72) by the smaller one (48) and check the remainder, which is 24. Since 24 evenly divides all the numbers (48, 72, 120), it serves as the GCD. Each of the 24 sets will include 2 blue crayons, 2 green crayons, 2 yellow crayons, 3 red crayons, and 5 colored pictures.

The formula for the box's volume is V = (length)(width)(height). If we denote the side length of the cutouts as x, we establish V = (28 - 2x)(22 - 2x)(x). Explanation: We intend to excise x by x squares from each corner of a 28 by 22-inch poster board, leading to bottom dimensions of 28 - 2x and 22 - 2x, with a height of x. This expression can be left as is or multiplied and simplified if desired. If we select x = 2 (a random choice as you did not specify), the box's volume calculates to V = (28 - 2*2)(22 - 2*2)(2), rendering V = (24)(18)(2) cubic inches. Since x measures length, it must be greater than zero. Furthermore, the base width of the box can't fall below zero, establishing the inequality for x: 22 - 2x > 0, meaning 11 - x > 0, or x < 11. If we check with x = 10, then V = (28 - 20)(22 - 20)(10). Is this greater than zero? YES. Thus, x < 11 is indeed a reasonable domain in this context.

The answer is A. 55. Explanation: For the 35%, take your 200 and divide it by 2 to yield two 100's. Since 35% equates to a portion of 100%, grab 35 from each 100 and sum them up to reach 70. For the proportion of 3/8, divide which results in 0.375 then multiply by 200 to ascertain that 75 are yellow tags. Adding 75 to 70 provides a total of 145, which when subtracted from 200 results in 55, indicating there are 55 red tags.

24 × 10 = 240
24 × 10 × 10 = 24 × 100 = 2400
24 × 10 × 10 × 10 = 24 × 1000 = 24000
24 × 10 × 10 × 10 × 10 = 24 × 10000 = 240000

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Answer:

24 × 10⁴

Answer:

The area of the new pumpkin patch can be represented as    =  15 x² + 380 x + 2400

Step-by-step explanation:

Given as:

The length of the original patch is L = 40 meters

The width of the original patch is W = 60 meters

Thus, the area of the rectangular patch is calculated as Length × Width

Or, =  L × W

So,    =  40 meters × 60 meters

Or,   =  2400 meters²

Moreover, the width of the new patch becomes (40 + 3 x) meters

And the length of the new patch becomes (60 + 5 x) meters

Or,  =  L × W

Thus,  =  (40 + 3 x) meters × (60 + 5 x) meters

Or,    = 2400 + 200 x + 180 x + 15 x²

Or,    =  15 x² + 380 x + 2400

Therefore, the area of the new pumpkin patch is given by    =  15 x² + 380 x + 2400  Answer