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Shkiper50
1 month ago
13

Grant Valley School has hired a fleet of buses and vans to transport 96 students to a picnic. Each bus can seat 31 people, and e

ach van can seat 9 people. The school authorities want to have three teachers traveling in each bus and one teacher in each van.
It will take to accommodate 107 people, including the students and teachers, with no seats left vacant.
NextReset
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Mathematics
2 answers:
tester [12.3K]1 month ago
5 0
Let x represent the number of buses and y represent the number of vans required to transport 107 individuals. 1. Since each bus accommodates 31 persons, with 3 being teachers, x buses can hold (31-3)x = 28x students. Each van has space for 9 individuals, with 1 designated for a teacher, thus y vans can accommodate (9-1)y = 8y students. 2. Grant Valley School requires transport for 96 students to this picnic, leading to the equation 28x + 8y = 96. 3. To accommodate a total of 107 individuals, including 96 students and teachers, the number of teachers is 107 - 96 = 11. The x buses will seat 3x teachers and the y vans will accommodate y teachers, giving us 3x + y = 11. 4. Solve the system of equations. Solve the first equation. Answer: 2 buses and 5 vans.
babunello [11.8K]1 month ago
4 0
2 buses and 5 vans............
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Mark and robyn used base-ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense whose model is nonsense?
babunello [11817]

Answer:

Robyn's model is logical, while Mark's is illogical.

Step-by-step explanation:

This question doesn't require calculations. What we need to do is analyze each model logically.

Mark's

Mark's representation indicates 20 instead of 2, which signifies that 200 is ten times greater than 20, making it nonsensical.

Robyn's

Robyn's representation displays 2, suggesting that 200 is 100 times greater than 2, which is not only accurate but also reasonable since 100 * 2 equals 200.

4 0
3 months ago
Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
AnnZ [12381]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
2 months ago
Read 2 more answers
Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36
tester [12383]

Answer:

Option 1 is valid, which entails 2 hours of walking and 12 hours of running.

Step-by-step explanation:

The equations provided are:

3w + 6r ≥ 36

3w + 6r ≤ 90

We'll assess which options comply with these equations.

1) 2 hours walking; 12 hours running

w = 2 and r = 12

3w + 6r ≥ 36

3(2) + 6(12) ≥ 36

6+72 ≥ 36

78 ≥ 36

3w + 6r ≤ 90

3(2) + 6(12) ≤ 90

6+72 ≤ 90

78 ≤ 90

Both equations are satisfied. Option 1 is valid.

2) 4 hours walking; 3 hours running

w = 4 and r = 3

3w + 6r ≥ 36

3(4) + 6(3) ≥ 36

12+18 ≥ 36

30 ≥ 36 (this does not hold since 30 < 36)

3w + 6r ≤ 90

3(4) + 6(3) ≤ 90

12+18 ≤ 90

30 ≤ 90

Thus, Option 2 is invalid.

3) 9 hours running; 12 hours walking

w = 9 and r = 12

3w + 6r ≥ 36

3(9) + 6(12) ≥ 36

27+72 ≥ 36

99 ≥ 36

3w + 6r ≤ 90

3(9) + 6(12) ≤ 90

27+72 ≤ 90

99 ≤ 90 (this does not hold since 99 > 90)

Option 3 is invalid.

4) 12 hours walking; 10 hours running

w = 12 and r = 10

3w + 6r ≥ 36

3(12) + 6(10) ≥ 36

36+60 ≥ 36

96 ≥ 36

3w + 6r ≤ 90

3(12) + 6(10) ≤ 90

36 + 60 ≤ 90

96 ≤ 90 (this does not hold since 96 > 90)

So, Option 4 is invalid.

3 0
3 months ago
F(x) = -4x(2)+ 12x – 9
AnnZ [12381]

For this context, we examine the function:

f (x) = - 4x ^ 2 + 12x-9

y = 0 presented as:

-4x ^ 2 + 12x-9 = 0

The definition of the discriminant in a quadratic equation is provided by:

a = -4\\b = 12\\c = -9

Sentences correspond to the types of roots: Different real roots, equal real roots, or distinct complex roots

d = b ^ 2-4 (a) (c)

d> 0:Upon substituting the provided values, we arrive at

d = 0:

d

This indicates that there are two equal real roots.

To discover the intersections along the x-axis, we apply the quadratic formula:d = (12) ^ 2-4 (-4) (- 9)\\d = 144-144

d = 0

Plugging in the values yields: y = 0:

-4x ^ 2 + 12x-9 = 0

The intersection on the x-axis is

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

x = \frac {-12 \pm \sqrt {12 ^ 2-4 (-4) (- 9)}} {2 (-4)}\\x = \frac {-12 \pm \sqrt {144-144}} {- 8}\\x = \frac {-12 \pm0} {- 8}\\x = \frac {-12} {- 8}\\x = \frac {3} {2}

(\frac {3} {2}, 0)

5 0
1 month ago
Read 2 more answers
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