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12 days ago

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The total cost of 5 doughnuts and 6 cookies at a bakery is $11.95.The cost of each cookie is $0.95.Select the equation and its s

olution that can be used to determine the cost,x, of 1 doughnut.

1 answer:

Zina [3.9K]12 days ago

6 0

The formula representing this scenario is $5x+6(0.95)=11.95$

The answer to this formula is $x=1.25$

Initially, you need to formulate the equation.

$5x+6(0.95)=11.95$

Next, simplify the expressions.

$5x+5.7=11.95$

Afterwards, subtract 5.7 from both sides.

$5x=6.25$

Lastly, divide both sides by 5

$x=1.25$

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zzz [4022]

Jawaban:

n(menang) = 6

n(seluruh) = 20

P(menang) = n(menang)/n(seluruh) = 6/20 = 3/10 atau 0,3 atau 30%

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8 days ago

What is the quotient (x3 – 3x2 + 3x – 2) ÷ (x2 – x + 1)?

tester [3916]

We have to calculate the result of the division problem.

$\frac{x^{3}-3x^{2}+3x-2}{x^{2}-x+1}$

To determine the result, long division will be employed.

$x^{2}-x+1$ ) $x^{3}-3x^{2}+3x-2$

Initially, we quotient with x since $x^{2}$ fits into $x^{3}$ , x times.

Thus, we have:

$x^{2}-x+1$ ) $x^{3}-3x^{2}+3x-2$ (x

$\text{..................}x^{3}-x^{2}+x$

After subtraction, we obtain:

$\text{....................}-2x^{2}+2x-2$

We can see that $x^{2}$ fits into $-2x^{2}$ , -2 times; therefore, the next addition to the quotient will be -2. This results in a final quotient of (x-2).

5 0

10 days ago

Read 2 more answers

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Svet_ta [4321]

Answer:

The shaped region accounts for 7/18 of the area of ACIG.

Step-by-step explanation:

Refer to the attached diagram for further clarity on the problem.

Step 1

Determine the length of one side of square ABED.

We know that

AB=BE=ED=AD

The area of a square can be calculated as

$A=b^{2}$

where b is the side length.

We have

$A=49\ units^2$

So we substitute

$49=b^{2}$

$b=7\ units$

Thus,

$AB=BE=ED=AD=7\ units$

Step 2

Calculate the area of ACIG.

The area of rectangle ACIG is determined by

$A=(AC)(AG)$

Substituting the given values yields

$A=(9)(10)=90\ units^2$

Step 3

Determine the area of the shaded rectangle DEHG.

The area of rectangle DEHG is given by

$A=(DE)(DG)$

We find $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

and substitute $A=(7)(2)=14\ units^2$

Step 4

Calculate the area of shaded rectangle BCFE.

The area of rectangle BCFE equals

$A=(EF)(CF)$

We see that

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

and substitute

$A=(3)(7)=21\ units^2$

Step 5

Add the areas of the shaded regions together.

$14+21=35\ units^2$

Step 6

Divide the area of the shaded region by the area of ACIG.

$\frac{35}{90}$

Simplify this fraction by dividing both the numerator and denominator by 5.

$\frac{7}{18}$

Hence, the shaped region represents 7/18 of the area of ACIG.

5 0

7 days ago

Sarah and her children went into a movie theater and she bought $35.50 worth of drinks and candies. Each drink costs $5 and each

AnnZ [3877]

Answer:

Sarah purchased 2 drinks and 6 candies.

Step-by-step explanation:

Let

x ----> the quantity of drinks Sarah bought.

y ----> the number of candies acquired by Sarah.

We know that

the total spent on drinks and candies was $35.50

therefore,

$5x+4.25y=35.50$ -----> equation A

She bought 3 times more candies compared to drinks.

thus,

$y=3x$ -----> equation B

To resolve the equations graphically

The solution lies at the intersection of the two graphs

utilizing a graphing tool

The result is the coordinate (2,6)

therefore,

Sarah bought 2 drinks and 6 candies.

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5 days ago

Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th

Zina [3914]

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

7 0

11 days ago