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Margaret
1 month ago
8

Brennan has been playing a game where he can create towns and help his empire expand. Each town he has allows him to create 1.15

times as many villagers as he had in the one before. The game gave Brennan five villages to start with. Explain to Brennan how to create an equation to predict the number of villagers in any specific town. Then show how to use your equation to solve for the number of villagers he can create to live in the 15th town. PLEASE HELP, I WILL GIVE BRAINLIEST!!
Mathematics
1 answer:
Inessa [12.5K]1 month ago
8 0
Let's break it down step by step: Brennan is engaged in a game where he can establish towns, helping his empire grow. He started with 5 villagers, with each town enabling him to add 1.15 times the number of existing villagers. After forming one town, he will have 5×1.15 villagers, and following the creation of two towns, he will have 5×1.15×1.15 villagers. After establishing three towns, it will be 5×1.15×1.15×1.15 villagers, and for n towns, it leads to. Thus, after creating 15 towns, he will have approximately 41 villagers. To create a formula predicting the number of villagers based on towns, let's denote the number of towns as n; consequently, the villagers can be summarized as.
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If the area of the vegetable garden is 170 square feet which equation could be of use to find the length of the tomato patch? 0=
Svet_ta [12734]

Answer:

The equation 0 = 3x² + 17x - 160 might be useful in determining the length.

Step-by-step explanation:

The area of the vegetable garden is specified as 170 ft².

Now, regarding the provided equations;

1) For 0 = 3x² + 2x + 180, applying the quadratic formula results in:

x = [-2 ± √(3² - 4(3 × 180)]/(2 × 3)

x = [-2 ± √(-2151)]/6

The square root value is negative, indicating no real solution for x.

Thus, this equation does not help find the length.

2) For the equation 0 = 3x² + 10x + 180, employing the quadratic formula, the square root value is also negative, hence there's no natural root for x. This means this equation can't be used to determine the length.

3) For 0 = 3x² + 17x - 160, the roots when using the quadratic formula yield -10.67 or 5. The value 5 is viable since it is a whole number. Considering the area is also a whole number, this equation can be applied to ascertain the length.

4) For 0 = 3x² - 160, simplifying gives;

3x² = 160

x² = 160/3

x = ±√(160/3)

x = ±7.303

Since the area is a whole number but this length isn't, this equation may not accurately determine the length.

5 0
3 months ago
You have a stack of pennies without counting the pennies, how can you know if there is a odd or even number of them
Zina [12379]

Imagine having a pile of pennies and you want to determine if the count is odd or even without tallying them one by one. You can separate them into pairs by placing one coin in the left pile and one in the right.

If no coin is left unmatched, then the total number is even; if there is one coin remaining unpaired, the number is odd.

 

8 0
3 months ago
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Rashal is adding the expression below. Negative 3 + left-bracket (negative 7) + (negative 6) right-bracket First, he rewrites th
Inessa [12570]
My guess is 3, but I'm uncertain.
6 0
1 month ago
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What is the distance from the point (3,8) to the point (7,-6)?
Leona [12618]

Answer: The distance is 14.6

Step-by-step explanation:

d = √((x2-x1)2 + (y2-y1)2)

(x2-x1) = (7 - 3) = 4

(y2-y1) = (-6 - 8) = -14

Sum it all up

(4)2 + (-14)2 = 16 + 196 = 212

Square 212

\sqrt{212} =14.5602

round to the nearest tenth

=

14.6

PLEASE MARK BRAINLIEST

5 0
2 months ago
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The germination rate is the rate at which plants begin to grow after the seed is planted.
lawyer [12517]

Response:

 z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59

 p_v =P(z  

Thus, the p value calculated came out to be quite small and based on the specified significance level

we can conclude that there is substantial evidence to dismiss the null hypothesis, indicating that at a 5% significance level the germination proportion of seeds is significantly below 0.9 or 90%\alpha=0.05p_v

Clarification:

Provided data and notation

n=15 indicates the random sample size taken

X=7 indicates the count of seeds that germinated

estimated proportion of seeds that sprouted

\hat p=\frac{7}{15}=0.467

indicates the hypothesized value we seek to test

p_o=0.9 represents the significance level used

z denotes the test statistic (variable under consideration)

signifies the p value (variable under consideration)  \alpha

Key concepts and formulas needed  

p_vWe will perform a hypothesis test to evaluate the assertion that the true rate of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:  

Alternative hypothesis:

 

In executing a proportion test, we employ the z statistic given by:  p\geq 0.9

(1)  p < 0.9The

One-Sample Proportion Test

is utilized to determine if a population proportion

significantly deviates from a proposed value

. z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}

Calculate the test statistic  \hat pSince all the necessary information is available, we can substitute into formula (1) like so:  p_o

 

Statistical conclusion  

It's critical to revisit the z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59p value method or p value approach

. "This approach assesses "likely" versus "unlikely" by determining the probability of observing a more extreme test statistic in line with the alternative hypothesis than the one observed, assuming the null hypothesis were true." In simpler terms, it is merely a method to establish a statistical decision on whether to reject or fail to reject the null hypothesis.  

The adopted significance level is . The following step would be to calculate the p value for this analysis.  As it is a left-tailed test, the p value would be:  

 Consequently, the p value shows a very low result and referencing the provided significance level

we can conclude we possess sufficient evidence to reject the null hypothesis, affirming that at the 5% level the proportion of germinated seeds is statistically significantly less than 0.9 or 90%

4 0
2 months ago
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