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Fed
6 days ago
7

Question Six

Business
1 answer:
harina [3.8K]6 days ago
5 0

Answer:

The estimated 90% confidence interval for the average depth of all frames in the consignment ranges from a lower boundary of 105.419 mm to an upper boundary of 106.581 mm.

Explanation:

The confidence interval for the mean is calculated as mean +/- margin of error (E)

mean = 106 mm

sample sd = 3.5mm

n is the sample size = 100

degree of freedom = n-1 = 100-1 = 99

confidence level (C) = 90% = 0.9

significance level = 1 - C = 1 - 0.9 = 0.1 = 10%

the critical value (t) for 99 degrees of freedom at a 10% significance level is 1.6602

E = t × sample sd/√n = 1.6602×3.5/√100 = 0.581 mm

Lower limit of mean = mean - E = 106 - 0.581 = 105.419 mm

Upper limit of mean = mean + E = 106 + 0.581 = 106.581 mm

The 90% confidence interval is (105.419 mm, 106.581 mm)

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Answer:

$311,100

Explanation:

Solution

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1 month ago
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soldi70 [3635]

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Below is the formula intended to be entered in cell C8:

=IF(C5>35000,IF(C5>25000<35000,IF(C5<25000,0.05*C5),0.04*C5),0.02*C5)

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