Part A
To identify the values of x that make 2x−1 positive
⇒ 2x - 1 > 0
⇒ 2x > 1
⇒ x > 
As a result, for any x greater than
, the expression 2x-1 is positive
Part B
To find values of y making 21−37 negative
⇒ 21-3y < 0
⇒ 21 < 3y
⇒ 7 < y
Thus, for all y values exceeding 7, the expression 21-3y is negative
Part C
To identify values of c that digit 5−3c greater than 80
⇒ 5-3c > 80
⇒ -3c > 75
⇒ -c > 25
⇒ c < -25
Therefore, for values of c less than -25, the expression 5-3c surpasses 80
Solution:
There are 4 ways.
Detailed explanation:
Candice has a total of 15 + 9 = 24 candies. Since she has three younger brothers, and 24 can be divided by 3 (24/3 = 8). Both 15 and 9 can also be divided by 3 (15/3 = 5 and 9/3 = 3).
- She can distribute 5 tootsie rolls to each brother.
- She can provide 3 twizzlers to each brother.
- She can give each brother 5 tootsie rolls and 3 twizzlers (if she decides to share all her candies).
- She can give them one of each type of candy, leaving her with 12 tootsie rolls and 6 twizzlers (this would be the best option if she wants to keep some for herself).
I see four methods to accomplish this, and two methods remain after her mother instructs her to share at least one of each candy type with all three brothers.
Answer:
15/28
Step-by-step explanation:
There are 28 participants total, with 15 being male, resulting in a fraction of 15/28
Utilizing the normal distribution and the central limit theorem, there's a 0.0284 or 2.84% chance of observing a sample mean mass of 695g or less.
The solutions to the equation are 
Explanation:
Given the equation 
, we aim to find the solutions of the equation.
Let us use 
and 
Thus, the equation transforms into
Factoring the equation results in:
Inserting back and allows us to solve for x.
Initially, we will substitute 
Consequently, we find;
Similarly, by substituting 
, we derive;
Thus, the solutions to the equation are
