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Firdavs
7 days ago
13

5. You deposit $300 in an account Urat pays 1.48% annual interest. What is the balance after 1 year if the

Mathematics
1 answer:
Svet_ta [12.7K]7 days ago
8 0

Answer:

The correct answer is (A) $304.47.

Step-by-step explanation:

The formula for calculating the future value (FV) of an amount (A), compounded daily at an interest rate of r%, over a period of n years is:

FV=A\times [1+\frac{r\%}{365}]^{n\times 365}

The provided information is:

A = $300

r% = 1.48%

n = 1 year

Calculate the future value as shown:

FV=A\times [1+\frac{r\%}{365}]^{n\times 365}

      =300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47

Thus, the balance at the end of 1 year totals $304.47.

The correct choice is (A).

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You are hiking and trying to determine how far away the nearest cabin is, which happens to be due north from your current positi
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Answer:

The cabin is located 567 yards away.

Step-by-step solution:

The bearing angle of 21.2° corresponds to the interior angle near the cabin in the triangle.

Apply the tangent function:

Opposite side length: 220 yards

Adjacent side length: x (distance to cabin)

tan(21.2°) = opposite / adjacent

tan(21.2°) = 220 yards / x

Multiply both sides by x:

x × tan(21.2°) = 220 yards

Isolate x:

x = 220 yards / tan(21.2°)

x = 220 / 0.388

x = 567 yards

Hence, the cabin is 567 yards away.

6 0
1 month ago
The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I
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Answer:

The correct option is:

On the coordinate plane, there is a parabola that opens upwards, passing through the points (2, 10), having its vertex at (5, 1), and intersecting (8, 10).

Step-by-step explanation:

Initially, we must understand the translation rules

1) {f(x) + a} signifies f(x) moved up by (a) units

2) {f(x) – a} means f(x) moved down by (a) units

3) {f(x + a)} represents f(x) moved left by (a) units.

4) {f(x – a)} indicates f(x) moved right by (a) units.

Given information:

f(x) = x²

g(x) = (x-5)² + 1

By comparing the transformation from f(x) to g(x) with the translation rules

It can be concluded that g(x) represents f(x) through a translation of 5 units to the right and 1 unit upwards (rules 1 and 4)

Refer to the attached image, which illustrates the graphs of both f(x) and g(x)

As depicted, g(x) intersects (2, 10), has a vertex at (5, 1), and crosses through (8, 10)

3 0
1 month ago
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For the month of June, Mae Green budgeted the following amounts: $180 for food, $475 for rent, $15 for transportation, $50 for i
tester [12383]
Question 1

Total budget sums up to 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990.
Actual expenditure amounts to 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36 = $1000.5.

Mae Green surpassed her designated budget.

---------------------------------------------------------------------------------------------------------

Question 2

Eleanor:
Earned = 380.48
Spent = 16.50

Peter:
Earned = 120 + 13.65 + 100 = 233.65.

Combined total income = 233.65 + 380.48 - 16.50 = 597.63.

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Question 3

Aggregate expenditure = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55.

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Question 4

Marie's updated balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50.

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Question 5

[235/825] × 100 = 28.48%
4 1
1 month ago
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Mr. And Mrs. Storey drove 3,200 miles in all during their vacation. Mr Storey drove 3 times as many miles as Mrs. Storey. Howany
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In the ratio of miles traveled, Mr. Storey and Mrs. Storey's journey is represented as mr: mrs = 3: 1. The total of these ratio units equals 4 (3+1), which means each unit corresponds to 3200 divided by 4, resulting in 800 miles. Mr. Storey drove 3 multiplied by 800, equating to 2400 miles, while Mrs. Storey drove 1 multiplied by 800, totaling 800 miles.
5 0
23 days ago
A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat
Inessa [12570]
To derive the function that characterizes the bee population:

1) Initially, there are 9,000 bees in the first year.

2) In the second year, a reduction of 5% occurs => 9,000 - 0.05 * 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95

3) Each subsequent year sees a 5% decline => 9,000 * (0.95)^(number of years)

4) Let x represent years and f(x) signify the bee count, then: f(x) = 9,000 (0.95)^x.

Evaluation of the claims:

<span>1) The function f(x) = 9,000(1.05)x applies to the scenario.

FALSE: WE ESTABLISHED IT AS f(x) = 9,000 (0.95)^x

2) The function f(x) = 9,000(0.95)x applies to the scenario.

TRUE: THIS IS THE RESULT OF OUR PRIOR ANALYSIS.

3) After 2 years, the farmer projects approximately 8,120 bees will be left.

Calculating:

f(2) = 9,000 * (0.95)^2 = 9,000 * 0.9025 = 8,122

Thus, this statement is TRUE

4) After 4 years, the farmer can predict there will be roughly 1,800 bees left.

f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330

This statement is therefore FALSE

5) The domain values contextual to this situation are restricted to whole numbers.

FALSE: DOMAIN VALUES INCLUDE ALL NON-NEGATIVE REAL NUMBERS. FOR INSTANCE, THE FUNCTION IS VALID AT X = 5.5

6) The range values pertinent to this situation are restricted to whole numbers.

TRUE: FRACTIONS OF BEES CANNOT EXIST.
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1 month ago
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