Which of the following functions is graphed below?

Answer:

A), B), and C) are clarified below.

Step-by-step explanation:

The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.

Simplifying gives us

P[k] = nCk / 2^n

A. Probability of all bits being 1s

16c16/2^16 = 1/65536

B. Probability of all bits being 0s

16c0/2^16 = 1/65536

C. The probability of having exactly 8 bits as 1s and the other 8 as 0s

16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%

Answer:

Step-by-step explanation:

The probability that a mosquito lands on your neck per second is 0.5

The chance of it biting once it lands is 0.2

The likelihood that it does not bite after landing is 0.8

Therefore, the probability of a bite in one second is

This translates to a 1/100 likelihood of being bitten in just one second

Over the course of 100 seconds, the expected number of bites is

The anticipated interval between bites is 100

Answer:

Step-by-step explanation:

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!

Answer:

Part 1) The algebraic expression can be represented as  or

Part 2) The algebraic expression is represented as

Step-by-step explanation:

Part 1) The expression (n-1) raised by 110%

Recognizing that

110%=110/100=1.10

thus,

The algebraic representation of (n-1) increased by 110% translates to 1.10 multiplied by (n-1).

Expanded

Part 2) The expression n^(-1) raised by 110%

110%=110/100=1.10

therefore, the representation of n^(-1) increased by 110% becomes 1.10 multiplied by n^(-1).

Remember that

thus,

Solution:

30% of the workforce consists of managers.

Explanation:

Given that there are 80 employees, out of which 24 are managers, we need to determine what percentage this represents.

This percentage can be calculated using the formula below:

By plugging in the known values, we have:

Thus, 30% of the employees are managers.