You have at most $3.65 to make copies for a school project. Each copy costs $0.25. Write and solve an inequality that represents

Answer:

A histogram will be utilized to illustrate the right wrist size of the random sample of newborn infants.

Step-by-step explanation:

A histogram serves as a visual representation of the frequency distribution present within the sample. Given that wrist circumference can take on positive real number values, a histogram with defined class boundaries can be constructed to display the overall distribution of wrist sizes in the graph.

Furthermore, as this distribution is continuous in nature, a histogram proves to be a fitting choice compared to either a bar graph or a stem-and-leaf plot.

Answer:

There is no notable difference between the two averages at a 5% significance level.

Step-by-step explanation:

A college student wanted to investigate whether business majors or liberal arts majors performed better in trivia.

The student administered a trivia quiz to 30 business majors, achieving an average score of 86. The same quiz was given to 30 liberal arts majors, with an average score of 89.

This process involved hypothesis testing to compare the means of two different disciplines. n =30

Since no specific claim is made regarding which group is better, a two-tailed test is appropriate.

The p-value achieved exceeds our alpha level,

indicating no significant difference exists between the average scores of the two groups, so we accept the null hypothesis.

Answer: The possible distances are 0.65 miles (away from the school) or 4.65 miles (towards the school).

Step-by-step explanation:

The information we have is as follows:

Total distance = 9.3 miles.

Journey:

House to school = 4 miles.

School to library = A

Library to house = B

From this, we know that:

4 miles + A + B = 9.3 miles.

We have three scenarios:

1) If the sequence is: house, library, school

The distance from school to library plus library to house would equal the distance from school to house = 4 miles.

Thus, A + B = 4 miles

4 miles + A + B = 8 miles ≠ 9.3 miles

Therefore, the library cannot be located between the house and school.

2) If the order is: house, school, library.

In this case, the distance from library to house would be the sum of the distance from house to school and from school to library:

4 miles + A = B.

Substituting this into our original equation:

4 miles + A + B = 9.3 miles

4 miles + A + (4 miles + A) = 9.3 miles

8 miles + 2*A = 9.3 miles

2*A = 9.3 miles - 8 miles = 1.3 miles

A = 1.3 miles / 2 = 0.65 miles

Thus, the distance from house to library is:

The 4 miles to school, plus the 0.65 miles from school to library:

Distance = 4 miles + 0.65 miles = 4.65 miles.

3) In the last case, the sequence is:

Library, house, school.

Here, the distance from house to library equals the difference between the distance from school to library and the distance from house to school:

A - 4 miles = B

Let's substitute this into our distance equation:

4 miles + A + B = 9.3 miles

4 miles + A + (A - 4 miles) = 9.3 miles

2A = 9.3 miles

A = 9.3 miles / 2 = 4.65 miles

Then the distance from house to library is:

B = A - 4 miles = 4.65 miles - A = 0.65 miles

So, the distance from house to library is 0.65 miles in this scenario.