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belka
1 month ago
15

The manufacturer of a laser printer reports the mean number of pages a cartridge will print before it needs replacing is 12,200.

The distribution of pages printed per cartridge closely follows the normal probability distribution and the standard deviation is 820 pages. The manufacturer wants to provide guidelines to potential customers as to how long they can expect a cartridge to last. How many pages should the manufacturer advertise for each cartridge if it wants to be correct 99% of the time
Mathematics
1 answer:
Leona [12.6K]1 month ago
5 0

Answer:

14110

Step-by-step explanation:

Let x = number of pages;

μ = 12200; σ = 820

Zscore = (x - μ) / σ

Zscore = (x - 12200) / 820

Zcritical for 99% confidence, with a one-tailed test equals 2.33

Hence, Z at 99% = 2.33

Substituting in for Zscore = 2.33

Zscore = (x - 12200) / 820

2.33 = (x - 12200) / 820

2.33 * 820 = x - 12200

1910.6 = x - 12200

1910.6 + 12200 = x

x = 14110.6

x = 14111

The number of pages to advertise for the cartridge is 14,110

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The accurate statements are 0.75 (x,y) = (0.75x, 0.75y), LM is parallel to L'M', and "the vertices of the image are nearer to the origin relative to the pre-image".

Explanation:

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DO, 0.75(x,y) signifies the dilation rule, where both x and y values are scaled by 0.75, indicating that the dilation, centered around the origin, has a scale factor of 0.75. The representation for this dilation would be,

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Consequently, the first statement holds true.

Since both x and y coordinates are scaled down by 0.75, the sides of the image are parallel, but shorter, with a scale of 0.75 compared to the pre-image’s sides.

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The scale factor of 0.75, being less than 1, suggests that the vertices of the image are closer to the origin compared to those of the pre-image.

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Part d) Refer to the explanation below.

Step-by-step explanation:

Please see the complete question in the attached image.

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y = 40

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x -----> define the volume of gasoline in gallons

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