Response:
#code (count_seq.py)
def count_seq():
n='2'
while True:
yield int(n)
next_value=''
while len(n)>0:
first=n[0]
count=0
while len(n)>0 and n[0]==first:
count+=1
n=n[1:]
next_value+='{}{}'.format(count,first)
n=next_value
if __name__ == '__main__':
gen=count_seq()
for i in range(10):
print(next(gen))
Clarification:
- Begin with the number 2. Utilize a string for easier manipulation rather than integers.
- Engage in an infinite loop.
- Yield the current integer value of n.
- Continue looping until n becomes an empty string.
- Repeat as long as n has content and the first digit matches the leading digit.
- Concatenate the count and the first digit to form next_value.