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Elis
1 month ago
11

Parallelogram FGHJ was dilated and translated to form

Mathematics
2 answers:
lawyer [12.5K]1 month ago
8 0
4 on edge.
babunello [11.8K]1 month ago
3 0
The dilation's required scale factor is 4.
You might be interested in
Which table contains only corresponding x-values and y-values where the value of y is one more than the product of x and 2?
zzz [12365]

Answer:

Option (C)

Step-by-step explanation:

The value of y exceeds the multiplication of x by 2.

The equation that describes this condition is:

y = 2x + 1

Thus, by inserting x values into this equation, we can produce a table reflecting the corresponding input and output values:

x        0       1         2        3        4

y         1        3        5        7        9

Consequently, the table provided in Option (C) is indeed the correct choice.

4 0
3 months ago
Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [12383]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
3 months ago
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