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Bas_tet
1 month ago
15

To help explain or predict the response variable in every regression study, we use one or more explanatory variables. These vari

ables are also called predictor variables or independent variables.
a. True
b. False
Mathematics
1 answer:
zzz [12.3K]1 month ago
8 0

Answer:

The accurate answer is False.

Step-by-step explanation:

In order to elucidate or forecast the response variable in any regression analysis, multiple explanatory variables are utilized. These are frequently referenced as response variables or dependent variables.

Risk factors and confounding variables are labeled as predictor or independent variables.

These definitions form a crucial part of regression analysis which is a method employed to evaluate the link between one or more risk factors and a designated outcome variable.

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Laura is the fund-raising manager for a local charity. She is ordering caps for an upcoming charity walk. The company that makes
Zina [12379]

Let x represent the number of caps

cost per cap = $6

cost for x caps = 6x

shipping charge = $25

overall budget = $1000

We can set up the following inequality:

Because the total amount cannot exceed 1000, we have

25 + 6x ≤ 1000

6x ≤ 975

x ≤ 162.5

rounding,

x ≤ 163

This means she can purchase a maximum of 163 caps.

5 0
3 months ago
Suppose R is plotted in the above coordinate plane and is collinear with A and B. If the ratio AR: AB is 1/3, then what are the
babunello [11817]
= -4/2 Step-by-step explanation: xp=x1 +k (x2-x1) = -3+1/3 (2- -3) = -3 + 1/3  (5/1) = -3 + 5/3 = -9/3 +5/3 = -4/2 Sorry, it doesn't look the best:)
3 0
2 months ago
Read 2 more answers
Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
Leona [12618]

Answer:

The total probability exceeds 100%, indicating a problem with the findings; moreover, the distribution shows excessive uniformity which disqualifies it as a normal distribution.

Detailed explanation:

The sum of probabilities should be exactly 100%. When you add the probabilities of this distribution:

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This exceeds 100%, highlighting a significant error in the results.

A typical normal distribution possesses a bell curve. If we plot the probabilities for this distribution, we'd see bars at 22, 24, 21, 26, and 28.

The bars would fail to form a bell-shaped curve, confirming that this is not a normal distribution.

3 0
3 months ago
Read 2 more answers
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Svet_ta [12734]

Response:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Detailed explanation:

In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:

Given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Applying the Poisson process, we find that

(a) at most 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) exactly 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) more than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) exactly 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) within the range of 10 to 15, inclusive

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
2 months ago
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