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Alja
1 month ago
15

Sue played four games of golf for these games her modal score was 98 and her mean score was 100 her range of score was 10 what w

as her score for the four games
Mathematics
1 answer:
zzz [12.3K]1 month ago
8 0

Answer: The other two observations are 97 and 107.

Explanation:

We know that

Mean = 100

Mode = 98

Range = 10

And from the formula,

Range = Highest - Lowest.

Let’s set the highest observation as x and the lowest as y.

Thus, we have the equation x - y = 10 (equation 1).

The observations can be represented as:

x, 98, 98, y.

Using the mean formula yields:

Mean = \frac{\text{Sum of observation}}{\text{N.of observaton}}.

This means our second equation is:

x + y = 204.

By applying the elimination method to solve these linear equations, we find:

x = 97.

and

x+y=204\\y=204-x\\y=204-97\\y=107.

Therefore, the other two observations are 97 and 107.

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The community college fine arts department sold three kinds of tickets to its latest dance presentation. The adult tickets sold
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Adult tickets sold = 75, Students = 200, Children = 75. To find the values, we use the variables for adult tickets, students, and children and set a series of equations based on the total tickets sold and both the pricing and quantity, leading to a solution of ticket counts.
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Two random samples are taken from private and public universities
babunello [11817]

Response:

Detailed explanation:

For private institutions,

n = 20

Average, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(sum of (x - mean)²/n

Sum of (x - mean)² = (43120 - 34623.05)^2 + (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public institutions,

n = 20

Average, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Sum of (x - mean)² = (25469 - 25063.15)^2 + (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This involves two independent samples. Define μ1 as the mean out-of-state tuition for private institutions and μ2 as the mean out-of-state tuition for public institutions.

The random variable represents μ1 - μ2 = the difference between the mean out-of-state tuition for private vs. public institutions.

The hypothesis is established as follows. The correct choice is

-B. H0: μ1 = μ2; H1: μ1 > μ2

As the sample standard deviation is known, the test statistic is calculated using the t test formula:

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The method for finding degrees of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

The probability value is obtained from the t test calculator. It is

p value = 0.000065

Given that alpha, 0.01 > the p value, 0.000065, we will reject the null hypothesis. Hence, at a significance level of 1%, the mean out-of-state tuition for private institutions is statistically significantly greater than that of public institutions.

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A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
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Response:

The coach should begin seeking players who weigh at least 269.55 pounds.

Step-by-step explanation:

We have these details from the question:

Average, μ = 225 pounds

Standard Deviation, σ = 43 pounds

The weights follow a bell curve, indicating a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We need to establish the value of x that corresponds to a probability of 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85

Review from the standard normal z table gives us:

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Consequently, the coach should start recruiting players weighing at least 269.55 pounds.

3 0
2 months ago
Five out of eight birds that visited the feeder ate the birdseed. If 60 ate the birdseed today, how many birds visited the feede
zzz [12365]

Answer:

96.

Step-by-step explanation:

Multiplica cruzado y divide para hallar la respuesta.

5/8 = 60/?

8 x 60 = 480.

480 / 5 = 96.

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1 month ago
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On a coordinate plane, a graph shows Street on the x-axis and Avenue on the y-axis. A line is drawn from Tia to Lei. Tia is at (
AnnZ [12381]

Answer:

B. Located at the intersection of 10th Street and 17th Avenue.

Step-by-step explanation:

The point (x,y) that divides segment AB with endpoints at A(x_1,y_1) and B(x_2,y_2) in the specified ratio m:n has coordinates

x=\dfrac{nx_1+nx_2}{m+n}\\ \\y=\dfrac{ny_1+ny_2}{m+n}

In this scenario,

T(4,8)

L(12,20)

The fruit market (F) is located three-fourths of the way from Tia’s residence to Lei's residence, hence TM:TL=3:4 or TM:ML=3:1

Therefore,

x=\dfrac{1\cdot 4+3\cdot 12}{3+1}=\dfrac{4+36}{4}=\dfrac{40}{4}=10\\ \\y=\dfrac{1\cdot 8+3\cdot 20}{3+1}=\dfrac{8+60}{4}=\dfrac{68}{4}=17

Thus, the fruit market lies at the location F(10,17) meaning it’s situated at the intersection of 10th Street and 17th Avenue.

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25 days ago
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