To determine the values of b that fulfill 3(2b+3)^2 = 36
we start with
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
Next, take the square root of both sides
(2b+3)} = (+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Thus,
the solutions for b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Utilizing commas makes it simpler to discern the figures.
6,289,002
The digit 6 occupies the millions spot. When rounding, if the subsequent digit is 5 or more, you will round up. Conversely, if the following digit is 4 or less, you will round down. Since the number following 6 is 2, rounding will lead to a decline. The closest million is therefore 6,000,000.
