Answer:
Explanation:
# Execute a Monte Carlo simulation 10k times
B <- 10000
results <- replicate(B, {
winners <- sample(runners, 3)
(winners[1] %in% "Jamaica" & winners[2] %in% "Jamaica" & winners[3] %in% "Jamaica")
})
mean(results)
Your question is missing the section C, so here is the C segment
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The data for the middle node shows as –250.... Please outline the pseudocode to substitute the middle node in the linked list. Assume that the head pointer is designated as Head_ptr and the entry data for the new node is defined as Entry.
Answer:
Refer to the explanation
Explanation:
Number of Mobiles=x1
Number of Workstations=x2
Constraints:
50x1 + 70x2 <= 1,60,000
250x1 + 700x2 <= 12,000,000
x1 >= 0 x2 >= 0
Objective function N(x1, x2) = 7800000000 x1 + 7200000000 x2
Excel formulae:
G17 = D9 * E7 + F9 * G7
G18= D10 * E7 * F10 * G7
G19= E7
G20= G7
G21= I17 * E7 + I18 * G7 (This will yield the Maximum)
And E7 and G7 will be the solution.
Set up your sheet as shown in the diagram and apply the formulas.
Access the tool and select solver. Upon opening the Solver dialog, confirm ‘Assume Linear model’ and ‘assume non-negative’. Click to solve the model and keep the solution.
int currentNumber,previousNumber = -1, countDuplicates = 0;
do {
cin >> currentNumber;
if ( previousNumber == -1) {
previousNumber = currentNumber;
}else {
if ( previousNumber == currentNumber )
countDuplicates++;
else
previousNumber = currentNumber;
}
} while(currentNumber > 0 );
cout << countDuplicates;
