Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
48 divided by 3 equals 16 (cups)
Adding 16 and 16 gives 32 (which is double the number of cups)
Thus, the number of plates is 16.
Provided the details regarding the sale prices of baseball cards from the 1960s:
It's established that they display a
skewed-right distribution
The average sale price is $5.25
The standard deviation measures $2.80.
If we draw a random sample of 100 cards
from that era:
The distribution will be Normal
The mean will remain at $5.25
The standard error turns out to be $0.28
<span>Starting with the equation f = v + at
Subtract v on both sides:
f - v = at
Divide both sides by a:
(f - v) / a = t
Swap the sides:
t = (f - v) / a
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