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blagie
11 days ago
8

Under what category of programs and apps do databases and enterprise computing fall?

Computers and Technology
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Allows you to manually add an entry to the arp cache that resolves the ip address inetaddr to the physical address etheraddr. wh
Amiraneli [1052]
In this situation, when the Adaptor or router gets the destination IP address (even if an incorrect MAC address is entered), it would strip the IP address from the Ethernet frame and using ARP, it will obtain the accurate MAC address of the destination.
6 0
2 months ago
Assume the int variables i,lo, hi, and result have been declared and that lo and hi have been initialized. Assume further that r
zubka84 [1067]

Answer:

#include <iostream>

using namespace std;

int main() {

   int i, lo=12, hi=45, result=0; // initializing the required variables..

   for(i=lo;i<=hi;i++) // implementing a for loop.

   {

       result+=i; // accumulating the sum of integers..

   }

   cout<<result<<endl; // displaying the resulting total.

return 0;

}

Output:-

969

Explanation:

This program is written in C++. Initially, the variables i, lo, hi, and result are declared, with only lo, hi, and result initialized. A for loop is employed to loop through all values from lo to hi, adding each integer to the result.

5 0
2 months ago
This question involves the creation of user names for an online system. A user name is created based on a user’s first and last
Rzqust [1037]

Response:

Refer to the explanation

Clarification:

import java.util.*;

class UserName{

ArrayList<String> potentialNames;

UserName(String fName, String lName){

if(this.isValidName(fName) && this.isValidName(lName)){

potentialNames = new ArrayList<String>();

for(int j=1;j<fName.length()+1;j++){

potentialNames.add(lName+fName.substring(0,j));

}

}else{

System.out.println("firstName and lastName should only consist of letters.");

}

}

public boolean isTaken(String name, String[] array){

for(int j=0;j<array.length;j++){

if(name.equals(array[j]))

return true;

}

return false;

}

public void removeUnavailableUserNames(String[] takenNames){

String[] namesArray = new String[this.potentialNames.size()];

namesArray = this.potentialNames.toArray(namesArray);

for(int j=0;j<takenNames.length;j++){

if(isTaken(takenNames[j],namesArray)){

int idx = this.potentialNames.indexOf(takenNames[j]);

this.potentialNames.remove(idx);

namesArray = new String[this.potentialNames.size()];

namesArray = this.potentialNames.toArray(namesArray);

}

}

}

public boolean isValidName(String str){

if(str.length()==0) return false;

for(int j=0;j<str.length();j++){

if(str.charAt(j)<'a'||str.charAt(j)>'z' && (str.charAt(j)<'A' || str.charAt(j)>'Z'))

return false;

}

return true;

}

public static void main(String[] args) {

UserName user1 = new UserName("john","smith");

System.out.println(user1.potentialNames);

String[] existing = {"harta","hartm","harty"};

UserName user2 = new UserName("mary","hart");

System.out.println("potentialNames prior to removal: "+user2.potentialNames);

user2.removeUnavailableUserNames(existing);

System.out.println("potentialNames following removal: "+user2.potentialNames);

}

}

8 0
3 months ago
A technique that’s used to route traffic to different destinations, depending on factors like location, congestion, or link heal
amid [951]
A method used to guide traffic to various destinations based on considerations like location, congestion, or link health is termed Anycast. It ranks among the top five techniques for Internet traffic routing, alongside unicast, broadcast, multicast, and geocast.
4 0
1 month ago
Read 2 more answers
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