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anastassius
8 days ago
6

The heights of a group of boys and girls at a local middle school are shown on the dot plots below. 2 dot plots with number line

s going from 40 to 60. A plot is titled Boy's Heights. There are 0 dots above 40, 1 above 41, 3 above 44, 3 above 46, 2 above 48, 3 above 50, 4 above 52, 4 above 54, and 0 above 56, 58, and 60. A plot is titled Girl's Heights. There are 0 dots above 40 and 41, 2 dots above 44, 3 above 46, 1 above 48, 3 above 50, 4 above 52, 3 above 54, 4 above 56, and 0 above 58 and 60. When comparing the shapes of the two sets of data, what conclusion can someone draw? The shortest boy is taller than the shortest girl. The range for the girls is greater than the range for the boys. There is an outlier in the data for the boys, but not for the girls. The girls are generally taller than the boys. on edge...
Mathematics
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Solve 4x - 5 = 7 + 4y for y
PIT_PIT [12445]

Answer:

y = x - 3

Step-by-step explanation:

4x - 5 = 7 + 4y  subtracting 7 from each side

4x - 12 = 4y

 then dividing every term by 4

x - 3 = y

3 0
2 months ago
Find the value of y if EF = EG.​
AnnZ [12381]

Answer:

55°

Step-by-step explanation:

The problem does not have a suitable diagram. Please check the attachment for the diagram.

Observing the diagram, it is evident that the triangle is isosceles, as it has two sides that are congruent (i.e., the same length). Since these sides are identical, the base angles are consequently also equal.

From the diagram, <EFG = <EGF

Since  <EFG  = 55°, it follows that  <EGF = y = 55°

Thus, the value of y is established as 55°

5 0
1 month ago
The side length, s, of a cube is x – 2y. If V = s3, what is the volume of the cube? x3 – 6x2y + 12xy2 – 8y3 x3 + 6x2y + 12xy2 +
Leona [12618]

V = x³ - 6x²y + 12xy² - 8y³

V = (x - 2y)³

   = (x - 2y)(x - 2y)(x - 2y) ( start by expanding the first pair of factors )

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  = x³ - 6x²y + 12xy² - 8y³




8 0
1 month ago
Read 2 more answers
If the roads leading to an arena can together handle 3,500 vehicles/hour of arena-only traffic, at what time should the roads be
Svet_ta [12734]
The given road capacity is 3,500 vehicles per hour, and the expected number of vehicles arriving is 14,000. To calculate the time required for these vehicles to access the arena:
14,000 vehicles divided by 3,500 vehicles per hour equals 4 hours.

If the event is scheduled to commence at 7 p.m., the roads should close at: 7 p.m. minus 4 hours, which results in 3 p.m.
4 0
2 months ago
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