Answer:
The y-intercept represents the number of minutes allocated for creating vegetable cans when no time is dedicated to fruit cans.
Step-by-step explanation:
The problem indicates that y refers to the minutes spent on vegetable can production, and the y-intercept indicates the y-value where x equals zero.
Thus, the y-intercept signifies the duration for producing vegetable cans when no time has been utilized for fruit can production.
To determine which functions depict the arithmetic sequence 8, 1.5, -5, -11.5,... follow these steps:
<span>f(n) = –6.5n + 14.5... correct
f(1) = 8
f(2) = 1.5
f(3) = -5
f(4) = -11.5
f(n) = –1.5n + 9.5... incorrect
f(1) = 8
f(2) = 6.5
f(n) = 6.5n + 1.5... incorrect
f(1) = 8
f(2) = 14.5
f(1) = 8, f(n + 1) = f(n) – 6.5... correct
f(2) = 8 - 6.5 = 1.5
f(3) = 1.5 - 6.5 = -5
f(4) = -5 - 6.5 = -11.5
f(1) = 8, f(n + 1) = f(n) – 1.5... incorrect
f(2) = 8 - 1.5 = 6.5
f(1) = 8, f(n + 1) = f(n) + 6.5... incorrect
f(2) = 8 + 6.5 = 14.5
The valid functions are:
</span>f(n) = –6.5n + 14.5 and f(1) = 8, f(n + 1) = f(n) – 6.5.
Answer:
At least 315
Step-by-step explanation:
A journalist intends to find the average annual salary of CEOs within the S&P 1,500. Due to time constraints, a sample is used.
Standard deviation of the sample (s) = 449300
Sample size = n
Permissible margin of error = 50000
Z critical value = 1.96
Thus, 1.96 times the standard error equals 50000.
Standard error equals 25510.20
Standard deviation divided by the square root of n = 25510.20
By simplifying, we can derive:
Thus, the minimum sample size required is 315.
Answer:
CrO₃.
Step-by-step explanation:
First, we will find the chromium percentage in the oxide by using the following process:
Oxygen (O) = 48%
Chromium (Cr) =?
The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:
Cr = 100 – percentage of oxygen
Cr = 100 – 48
Cr = 52%
Next, we will determine the empirical formula for the oxide:
Chromium (Cr) = 52%
Oxygen (O) = 48%
Now, we divide by their molar mass:
Cr = 52/52 = 1
O = 48/16 = 3
Now, divide by the lowest value:
Cr = 1/1 = 1
O = 3/1 = 3
Thus, the empirical formula for the oxide is CrO₃.
