Answer How much of a 20% acid solution should be blended with 30 liters of a 50% acid solution in order to achieve a 40% solution.... x=15 liters 15*(.20 pure acid)=3 liters 30*(.50 pure acid)=15 liters That totals 18 liters of pure acid, resulting in a final mixture of 45 liters which contains 0.45 pure acid=18 liters.
Step-by-step explanation:
Answer: F(x) > 0 in the ranges (-0.7, 0.76) and (0.76, ∞).
I hope this is useful:)
1.4×5=7
0.8×10=8
1.4×10=14
1×15=15
15+14+8+7=44
44÷4=11
LQ of 44=11
LQ=10 minutes
11×3=33
UQ= 29 minutes
The Range is 19 minutes
Detailed breakdown:
Commence with the individual boxes. For determining the number of students in each category, calculate Frequency density × The difference in the category. (if it's 5-15, the difference is 10)
This results in the counts of students in each range.
Next, determine the LQ of 44, which is 11.
Then locate the 11th student's score; in this instance, it resides in the 5-15 range. 7 students have already surpassed it, with 8 in the 5-15 range. Hence, the 11th lies within the bounds of 5-15, making the middle 10.
Repeat this process for the UQ.
The interquartile range is calculated as UQ-LQ, yielding 29-10=19 minutes.
I hope this helps, though I'm not entirely sure if my explanation is coherent and I'm unclear on the terminology I've used for these categories.
Answer:
According to my cupcake recipe, it yields $12$ cupcakes and calls for $1\frac{1}{2}$ sticks of butter. I can only purchase whole sticks of butter.
Consequently, a single whole stick of butter will suffice to prepare $100$ cupcakes.
