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Shtirlitz
16 days ago
7

Analia is a school district manager. Here are some details about two schools in her district for the last school year: School A

School B Number of students 300030003000 400040004000 Number of teachers 190190190 380380380 Graduation rate 86\%86%86, percent 90\%90%90, percent Budget per student \$10{,}500$10,500dollar sign, 10, comma, 500 \$10{,}000$10,000dollar sign, 10, comma, 000 % of students in sports club 62\%62%62, percent 68\%68%68, percent Number of sports medals won 999 777 SAT average 120012001200 105010501050 SAT range (max-min) 900900900 700700700 Analia wants to know which school has higher athletic achievements relative to the SAT average. 1) Analia thought of two different ways to define this quantity. Identify these two definitions among the following options.

Mathematics
2 answers:
Leona [4.1K]16 days ago
4 0

Answer:

It involves the percentage of students in the sports club divided by the SAT average, and the number of sports medals awarded divided by the SAT average. The second response is no; the definitions yield opposing results.

Step-by-step explanation:

Khan academy

tester [3.9K]16 days ago
4 0

Answer:

Step-by-step explanation:

For question 1, the result is calculated by dividing the percentage of students in the sports club by the SAT average, while for question 2, the answer is no since the definitions yield contrary outcomes.

You might be interested in
out of fifty students,34 joined the journalism class and 25 joined robotics club.if 16 students joined both clubs,how many stude
AnnZ [3877]

Answer:

Step-by-step explanation:

Overall students=50

35 -> j.

25 -> r.

16-> j.+r.

35-16=19 students joined j.

25-16=9 joined r.

50-19+9

50-28=22

The answer is 22

It would be nice if you could give me the brainliest rating. Best of luck!

3 0
2 days ago
What is the empirical formula of an oxide of chromium that is 48 percent oxygen by mass?
Svet_ta [4321]

Answer:

CrO₃.

Step-by-step explanation:

First, we will find the chromium percentage in the oxide by using the following process:

Oxygen (O) = 48%

Chromium (Cr) =?

The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:

Cr = 100 – percentage of oxygen

Cr = 100 – 48

Cr = 52%

Next, we will determine the empirical formula for the oxide:

Chromium (Cr) = 52%

Oxygen (O) = 48%

Now, we divide by their molar mass:

Cr = 52/52 = 1

O = 48/16 = 3

Now, divide by the lowest value:

Cr = 1/1 = 1

O = 3/1 = 3

Thus, the empirical formula for the oxide is CrO₃.

4 0
8 days ago
A statistician at a metal manufacturing plant is sampling the thickness of metal plates. If an outlier occurs within a particula
babunello [3635]

Answer: 26.3 mm

Step-by-step explanation:

The two-standard deviations rule for outliers states that any value lying outside two standard deviations from the average is considered an outlier.

Given that the Mean is 23.5 millimeters (mm) and the standard deviation is 1.4 mm

The maximum thickness that should be reviewed = mean + 2 (standard deviation)

= 23.5 + 2(1.4)

= 23.5 + 2.8

= 26.3 mm

therefore, the maximum thickness warranting machine configuration review by the statistician = 26.3 mm.

7 0
15 days ago
Erika is writing a coordinate proof to show that the diagonals of a rectangle are congruent. She begins by assigning coordinates
Leona [4166]

Answer:

Option C is the right choice.

Step-by-step explanation:

The given coordinates define a rectangle, and our objective is to show that the diagonals JL and KM are congruent.

We know that rectangles possess four right angles.

To prove the congruence of the diagonals JL and KM, we will utilize the Pythagorean theorem.

In triangle KLM, KL has a length of b units while LM has a length of a units. By applying the Pythagorean theorem \sqrt(a^{2}+b^{2})=KM

In triangle JML, JM is b units long, and LM remains a units long. We again can apply the Pythagorean theorem \sqrt(a^{2}+b^{2})=JL

Thus, we find that \sqrt(a^{2}+b^{2})=KM=LM and option C is the correct choice.

7 0
4 days ago
Read 2 more answers
Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
Leona [4166]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0
12 days ago
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