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Novosadov
2 months ago
3

For any meeting (other than the agile events) that team members have among them, what are the points to consider? (select two co

rrect answers)
1. Team must keep number of such meetings minimal.


2. Team must not allow such meetings to go beyond an hour.


3. Team must keep duration of such meetings short and timebox based on the agenda.


4. Team meetings (other than agile events) need not be timeboxed.
Computers and Technology
2 answers:
maria [1K]2 months ago
5 0

Answer:

1. The number of such meetings should be kept to a minimum.

3. These meetings ought to be brief and confined in duration based on the agenda.

Explanation:

In considering any meeting (excluding agile events) that occurs amongst team members, two main factors must be kept in mind;

- maintaining a low frequency of these meetings.

- ensuring that the length of the meetings is short and focused according to the agenda.

Harlamova29_29 [1K]2 months ago
5 0

Answer:

  • The number of such meetings needs to be limited.
  • The duration of these meetings should be kept short and organized according to the agenda.

Explanation:

For gatherings that do not qualify as agile events (which are crucial for team members to attend), it is vital to reduce how often these meetings occur. If they are held, they should be time-boxed to prevent team members from becoming disinterested or bored.

Team meetings, apart from agile events, must not be unregulated or lack time constraints, which is why options 1 and 3 are the correct choices.

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In this code, identify the repeated pattern and replace it with a function called month_days, that receives the name of the mont
8_murik_8 [964]

Answer:

Below is the month_days function:

def month_days(month, days):

 print (month +" has " + str(days) + " days.")

You can invoke this function with arguments like:

month_days ("June", 30)

month_days("July", 31)

The function can also be restructured as follows:

def month_days(month, days):

 return (month +" has " + str(days) + " days.")

To view the output, call the function along with print like this:

print(month_days ("June", 30))

print(month_days("July", 31))

Explanation:

The defined month_days function takes two parameters: the month name and the number of days in that month. It has a return statement return (month +" has " + str(days) + " days.") which combines the month name held in the variable month with the word "has" and then the number of days stored in days followed by the term days.

For instance, if "June" is passed in as month and 30 as days, the output will be:

June has 30 days.

This program can also be constructed using an f-string for better formatting in the month_days function:

def month_days(month, days):

   output = f"{month} has {days} days."

   return (output)

To see the output, invoke the function with print:

print (month_days("June", 30))

print (month_days("July", 31))

The f-string starts with 'f' and includes the parameters month and days within curly braces. The variables month and days are substituted with their respective values when the function is called.

Screenshot of the program and its output is attached.

6 0
2 months ago
A video conferencing application isn't working due to a Domain Name System (DNS) port error. Which record requires modification
Rzqust [1037]

Answer:

Service record (SRV)

Explanation:

Service records, known as SRV records, contain information defining aspects of the DNS like port numbers, server details, hostnames, priority, weight, and the IP addresses of designated service servers.

The SRV record serves as a valuable reference for locating specific services, as applications needing those services will search for the corresponding SRV record.

When configured, the SRV provides the necessary ports and personal settings for a new email client; without this, the parameters within the email client will be incorrect.

8 0
2 months ago
(Java) Which of the following code segments correctly declare a Strings and gives it a value of "fortran".
maria [1035]

Response:

IT F

Clarification:

8 0
2 months ago
Write the pseudocode that determines the change to be dispensed from a vending machine. An item in the machine can cost between
Amiraneli [1052]

Answer:

input price

set change to one hundred minus price

set quarter to change divided by 25

set change to change mod 25

set dime to change divided by 10

set change to change mod 10

set nickel to change divided by 5

set change to change mod 5

set penny to change

print "You acquired an item for price cents and paid me a dollar. Your change is: "

if quarter is equal to 1

print quarter

else if quarter is greater than 1

print quarter with "quarters"

if dime is equal to 1

print dime

else if dime is greater than 1

print dime with "dimes"

if nickel is equal to 1

print nickel

else if nickel is greater than 1

print nickel with "nickels"

if penny is equal to 1

print penny

else if penny is greater than 1

print penny with "pennies"

Explanation:

A clearer way to express the pseudocode above could involve using alternative names for change as:

input price

set change to one hundred minus price

set quarter to change divided by 25

set quarter_remainder to change mod 25

set dime to quarter_remainder divided by 10

set dimes_remainder to quarter_remainder mod 10

set nickel to dimes_remainder divided by 5

set nickel_remainder to dimes_remainder mod 5

set penny to nickel_remainder

print "You purchased an item for" price"cents and provided a dollar. Your change is: "

if quarter is equal to 1

print quarter "quarter"

else if quarter is greater than 1

print quarter "quarters"

if dime is equal to 1

print dime "dime"

else if dime is greater than 1

print dime "dimes"

if nickel is equal to 1

print nickel "nickel"

else if nickel is greater than 1

print nickel "nickels"

if penny is equal to 1

print penny "penny"

else if penny is greater than 1

print penny "pennies"

Next, I will illustrate the pseudocode through an example:

Let's assume price = 75

Thus, change = 100 - price = 100 - 75 = 25

change = 25

quarter = change/25 = 25/25 = 1

quarter = 1

quarter_remainder = change % 25 = 25%25 = 0

dime = 0/10 = 0

At this point, all additional values are 0.

The following message will be displayed on the screen:

You acquired an item for 75 cents and paid me a dollar. Your change is:

Now the program proceeds to the conditional statement

if quarter == 1

This condition holds true because the value of quarter is 1

print quarter "quarter"

Subsequently, this line will appear on the screen:

1 quarter

Thus, the full output of the pseudocode is:

You acquired an item for 75 cents and paid me a dollar. Your change is:

1 quarter

6 0
22 days ago
python Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value i
oksian1 [950]

int currentNumber,previousNumber = -1, countDuplicates = 0;

do {

cin >> currentNumber;

if ( previousNumber == -1) {

previousNumber = currentNumber;

}else {

if ( previousNumber == currentNumber )

countDuplicates++;

else

previousNumber = currentNumber;

}

} while(currentNumber > 0 );

cout << countDuplicates;

7 0
2 months ago
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