A group of 5 friends decides to share the cost of a party together. If the party costs $1,100, how much does each friend pay?

Given data for different baseball teams’ number of home runs and wins for the past season, how would you find the equation of th

lawyer [12517]

To find the desired amount, compare the home runs to the wins to demonstrate the impact of homers on the winning outcomes

. Use x for the wins and y for the number of home runs each time they win

. Initially, you can create a bar graph, followed by a line graph to illustrate how home runs influence victories

. I hope this is useful.

7 0

2 months ago

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The final velocity, V, of an object under constant acceleration can be found using the formula uppercase V squared = v squared +

zzz [12365]

The equation resolved for a is StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a.

8 0

2 months ago

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Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

babunello [11817]

Answer:

0.75 = 75% chance that only one tag is lost, provided at least one tag is lost

Step-by-step explanation:

Independent events:

If A and B are independent events, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

Here

P(B|A) refers to the probability of event B occurring, given that event A has occurred.

$P(A \cap B)$ is the probability of both A and B occurring together.

P(A) is the probability of event A occurring.

In this scenario:

Event A: At least one tag is missing

Event B: Only one tag is missing.

Each tag has a 40% likelihood of being lost, which is equal to 0.4.

Probability of at least one tag missing:

The events can be considered as either no tags are missing or at least one is. Their probabilities sum to 1. Thus

$p + P(A) = 1$

p is the probability that none are lost. Each tag has a 60% = 0.6 chance of not being lost, and since they are independent,

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection of at least one lost (A) and exactly one lost (B) is precisely one lost.

Then

Probability of at least one lost:

The first being lost (0.4 chance) and the second not lost (0.6 chance)

Or

The first not being lost (0.6 chance) and the second lost (0.4 chance)

So

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Calculate the probability that exactly one tag is lost, given that at least one tag is lost (round to two decimal places).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% likelihood that precisely one tag is lost, assuming at least one tag is lost

8 0

2 months ago

Drainage tubing comes in large rolls. At your hardware store, you cut tubing to the lengths the customers want. You also provide

Leona [12618]

Answer: $\frac{1}{36}\pi L$

Step-by-step explanation:

The volume of a cylinder is calculated using the formula:

$V=\pi r^2h$

In which "r" represents the radius and "h" is the height.

Convert inches to feet. Given that $1\ ft=12\ in$ , the result is:

$(2\ in)(\frac{1\ ft}{12\ in})=\frac{1}{6}\ ft$

Therefore, you can determine:

$r=\frac{1}{6}\\\\h=L$

After substituting these values into the formula and simplifying, the result is:

$V=\pi(\frac{1}{6})^2L\\\\V=\frac{1}{36}\pi L$

Consequently, the equation representing the volume of L feet of drainage tubing, in cubic feet, is:

$\frac{1}{36}\pi L$

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3 months ago

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