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valina
11 days ago
8

Factor completely 7x3y +14x2y3 − 7x2y2.

Mathematics
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Quadrilateral FRIO is the result of a reflection of quadrilateral LAMB over the y-axis. FRIO has vertices at F(-7,6), R(1,7), I(
Inessa [12570]

Answer:

F' = (7, 6)

R' = (-1, 7)

I' = (-2, -5)

O' = (6, -6)

Step-by-step explanation:

The reflection rule across the y-axis states that (x, y) ---> (-x, y). Thus, all x coordinates must be converted to their negative counterparts. The -7 from F becomes 7, the 1 from R becomes -1, the 2 from I turns into -2, and the -6 from O changes to 6.

3 0
3 months ago
the number of years that brad has been on the soccer team is 2 less than 5 times the number of years that scott has in total the
PIT_PIT [12445]
Let the number of years Brad has been on the soccer team be represented by x, and let y represent the number of years Scott has been on the same team.

From the information given, we formulate the equations:
5y - 2 = x -----(1)

x + y = 10 -----(2)

Now, substituting equation (1) into equation (2):
5y - 2 + y = 10
6y - 2 = 10
6y = 12
y = 2
Next, substituting this value back to find x:
x = 5×2 - 2
x = 8

So, Brad has spent a total of 8 years in the team.
8 0
3 months ago
Which table shows a function that is decreasing only over the interval (–1, ∞)? A 2-column table with 6 rows. The first column i
Inessa [12570]
B. f(x) ≤ 0 over the interval [0, 2]. D. f(x) > 0 over the interval (–2, 0). E. f(x) ≥ 0 over the interval [2, ).
8 0
2 months ago
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Inessa [12570]

Response:

The coach should begin seeking players who weigh at least 269.55 pounds.

Step-by-step explanation:

We have these details from the question:

Average, μ = 225 pounds

Standard Deviation, σ = 43 pounds

The weights follow a bell curve, indicating a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We need to establish the value of x that corresponds to a probability of 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85

Review from the standard normal z table gives us:

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Consequently, the coach should start recruiting players weighing at least 269.55 pounds.

3 0
3 months ago
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