I believe this is <span>Commensalism since the bird gains a benefit while the cow is neither helped nor harmed.</span><span />
The right answer is B. DNA helicase initially unwinds the double helix surrounding the +1 site.
An individual who possesses two identical X chromosomes is female.
Since women have a pair of X chromosomes, they are considered homozygous for the X chromosome - the term homozygous refers to having 'two chromosomes of the same type.' In contrast, men typically have different chromosome types - XY.
The resultant sequence would be: UAGCAU. U pairs with A, while C pairs with U. Hope this helps! Photon.
<span>The result hinges on the type of non-random mating involved. In the case of positive assortative mating, it typically raises the frequencies of homozygous genotypes, as it occurs when individuals pair with similar individuals. Conversely, if the non-random mating is negative assortative, the outcome mirrors that of positive assortative mating, resulting in a decrease in the frequencies of homozygous genotypes.</span>
