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9 days ago

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At the warm-up event for Oscar’s All Star Hot Dog Eating Contest, Al ate one hot dog. Bob then showed him up by eating three hot

dogs. Not to be outdone, Carl ate five. This continued with each contestant eating two more hot dogs than the previous contestant. How many hot dogs did Zeno (the 26th and final contestant) eat? How many hot dogs were eaten all together?

1 answer:

Inessa [3.9K]9 days ago

5 0

Answer: Zeno consumed 51 hot dogs.

The total number of hot dogs consumed was 676.

Step-by-step explanation:

Al started by eating one hot dog. Bob then outperformed him by devouring three hot dogs. Carl, not wanting to fall behind, ate five hot dogs. This pattern continued, with each participant consuming two hot dogs more than the previous one. This indicates that the quantity of hot dogs eaten by each contestant followed an arithmetic sequence.

The formula for finding the nth term in an arithmetic series is given by

Tn = a + (n - 1)d

Where

a denotes the first term in the sequence.

d signifies the common difference.

n stands for the total terms in the sequence.

<pBased on the details provided,

a = 1 hot dog

d = 3 - 1 = 2 hot dogs

We aim to find how many hot dogs the 26th contestant, T26, consumed. Thus,

T26 = 1 + (26 - 1)2 = 1 + 50

T26 = 51 hot dogs

The formula to calculate the sum of n terms in an arithmetic sequence is

Sn = n/2[2a + (n - 1)d]

Hence, to find the total number of hot dogs consumed by 26 contestants, S26 is calculated as

S26 = 26/2[2 × 1 + (26 - 1)2]

S26 = 13[2 + 50]

S26 = 13 × 52 = 676 hot dogs

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The measurement labeled as 'a' is larger than 'b' since those equal sides are longer than the base. Given "one of the longer sides measures 6.3 cm," we assign a = 6.3.

Substitute 6.3 for each 'a' in the equation and solve for b:
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16 days ago

A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150

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Answer:

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Part 3) The valid domain consists of all real numbers exceeding zero and below 75 meters

Step-by-step explanation:

Part 1) Formulate an expression for A(x)

Let

x -----> the length of the rectangular school yard

y ---> the width of the rectangular school yard

It is known that

The perimeter for the fencing (taking the school wall as one side) is

$P=2x+y$

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thus

$150=2x+y$

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The area of the rectangular school yard is

$A=xy$ ----> this is equation B

Substituting equation A into equation B yields

$A=x(150-2x)$

$A=150x-2x^2$

Change to function notation

$A(x)=150x-2x^2$

Part 2) What is the area when x=40?

With x equal to 40 m

substitute the value into the expression from Part 1 to determine A

$A(40)=150(40)-2(40^2)$

$A(40)=2,800\ m^2$

Part 3) What would be a suitable domain for A(x) in this scenario?

We understand that

A signifies the area of the rectangular school yard

x characterizes the length of the rectangular school yard

It follows that

$A(x)=150x-2x^2$

This forms a vertical parabola opening downwards

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The x-coordinate of the vertex corresponds to the length that maximizes the area

The y-coordinate of the vertex denotes the maximum area

The vertex corresponds to (37.5, 2812.5)

Refer to the accompanying figure

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The peak area achieved is 2,812.5 m^2

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The domain for A is the range -----> (0, 75)

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11 days ago

The area of the postcard is 24 square inches. What is the width b of the message (in inches)?

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Substitute into the area formula:
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14 days ago

10 times as many as blank hundreds or 60 hundreds is blank thousands

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The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

10 times a given quantity of _____ hundreds results in 60 hundreds
60 hundreds convert to _____ thousands

We will divide this into two segments:

$\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }$ ... Equation-1

$\boxed{ \ 60 \times 100) = M \times 1,000 \ }$ ... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

$\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }$

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Both parts will be divided by 1,000, essentially being multiplied by $\frac{1}{1,000}$ .

$\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }$

Thus, we conclude with $\boxed{\boxed{ \ N = 6 \ }}$

Next, we process Equation-2 to derive M's value.

$\boxed{ \ 60 \times 100) = M \times 1,000 \ }$

$\boxed{ \ 6,000 = M \times 1,000 \ }$

Rearranging this equation to place M on the left side appears as follows:

$\boxed{ \ M \times 1,000 = 6,000 \ }$

Again, both sides undergo division by 1,000, which translates to multiplication by $\frac{1}{1,000}.$ .

$\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }$

This results in $\boxed{\boxed{ \ M = 6 \ }}$

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

$\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }$

$\boxed{ \ 6 \times thousands = \ M \ thousands} \ }$

$\boxed{\boxed{ \ M = 6 \ }}$

Additional resources

A more detailed version of this topic
2 thousands 7 tens divided by 10 equals what?
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Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

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