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Luba_88
9 days ago
5

Michael uses a blend of dark chocolate and milk chocolate to make the ice cream topping at his restaurant. He needs to buy 100\,

\text{kg}100kg100, start text, k, g, end text of chocolate in total for his next order. Dark chocolate costs \$12$12dollar sign, 12 per kilogram, milk chocolate costs \$10$10dollar sign, 10 per kilogram, and he wants to spend \$1120$1120dollar sign, 1120 total. Let ddd be the number of kilograms of dark chocolate he buys and mmm be the number of kilograms of milk chocolate he buys.
Mathematics
1 answer:
AnnZ [3.8K]9 days ago
7 0

Answer:

Michael purchases 60 kg of dark chocolate alongside 40 kg of milk chocolate.

Step-by-step explanation:

Let d signify the kilograms of dark chocolate bought by Michael and m signify the kilograms of milk chocolate he acquires.

He must acquire a total of 100 kg of chocolate, thus

d+m=100

With dark chocolate priced at $12 per kg, the cost for d kg would be $12d. The price of milk chocolate is $10 per kg, indicating the cost for m kg is $10m. Michael intends to spend $1,120 on the chocolate, therefore

12d+10m=1,120

Taking the first equation

d=100-m

By inserting this into the second equation:

12(100-m)+10m=1,120\\ \\1,200-12m+10m=1,120\\ \\-12m+10m=1,120-1,200\\ \\-2m=-80\\ \\m=40\\ \\d=100-m=100-40=60

Michael ends up buying 60 kg of dark chocolate and 40 kg of milk chocolate.

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